Problem of generating 4 sub-images

1 visualización (últimos 30 días)
gg
gg el 14 de Nov. de 2013
Editada: Image Analyst el 15 de Nov. de 2013
I want to divide a color image into 4 sub-images which are also needed to be color images. However, I got the wrong images for my implementation. Please help me. Thanks!
% I= double(imread('2.jpg'));
% [m,n] = size(I);
%
% r = I(:,:,1); % Get the RED matrix
% g = I(:,:,2); % Get the GREEN matrix
% b = I(:,:,3); % Get the BLUE matrix
%
% [m,n] = size(r);
%
% imgr{1} = r(1:m/2, 1:n/2);
% imgr{2} = r(m/2+1:m, 1:n/2);
% imgr{3} = r(1:m/2, n/2+1:n);
% imgr{4}= r(m/2+1:m, n/2+1:n);
%
% imgg{1} = g(1:m/2, 1:n/2);
% imgg{2} = g(m/2+1:m, 1:n/2);
% imgg{3} = g(1:m/2, n/2+1:n);
% imgg{4}= g(m/2+1:m, n/2+1:n);
%
% imgb{1} = b(1:m/2, 1:n/2);
% imgb{2} = b(m/2+1:m, 1:n/2);
% imgb{3} = b(1:m/2, n/2+1:n);
% imgb{4}= b(m/2+1:m, n/2+1:n);
%
% final_image1(:,:,1)= imgr{1};
% final_image1(:,:,2)= imgg{1};
% final_image1(:,:,3)= imgb{1};
%
% final_image2(:,:,1)= imgr{2};
% final_image2(:,:,2)= imgg{2};
% final_image2(:,:,3)= imgb{2};
%
% final_image3(:,:,1)= imgr{3};
% final_image3(:,:,2)= imgg{3};
% final_image3(:,:,3)= imgb{3};
%
% final_image4(:,:,1)= imgr{4};
% final_image4(:,:,2)= imgg{4};
% final_image4(:,:,3)= imgb{4};
%
% filename = {final_image1,final_image2,final_image3,final_image4};
% q={'a1.bmp','a2.bmp','a3.bmp','a4.bmp'};
%
% for i=1:4
% imwrite(filename{i},q{i},'bmp');
% end

Respuestas (3)

Simon
Simon el 14 de Nov. de 2013
Hi!
What exactly is going wrong?
  5 comentarios
Simon
Simon el 15 de Nov. de 2013
You do not neccesarily need the "uint8" conversion of "I" upon splitting the image. If "I" was not defined as double before it will automatically be of class uint8 after "imread".
Image Analyst
Image Analyst el 15 de Nov. de 2013
Editada: Image Analyst el 15 de Nov. de 2013
Wow, you really like to have a lot of code don't you? You could have done it in far less space simply by using imcrop() as I and David recommended. See demo code that I added in my answer to show you how simple it can be.

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Image Analyst
Image Analyst el 14 de Nov. de 2013
Editada: Image Analyst el 15 de Nov. de 2013
Why not simply use imcrop() ? It would take far far fewer lines of code.
And when you do n/2, if n is an odd number, you'll get a .5 fraction off the end of the number and that will not let you do 1:n/2, so you need to do
n1 = floor(n/2);
n2 = n1+1;
Then go from 1 to n1 and from n2 to end.
[rows, columns, numberOfColorChannels] = size(rgbImage);
c1 = floor(columns/2); % Middle column
c2 = c1+1;
r1 = floor(rows/2); % Middle row
r2 = r1+1;
upperLeft = imcrop(rgbImage, [1, 1, c1, r1]);
upperRight = imcrop(rgbImage, [c2, 1, c1, r1]);
lowerLeft = imcrop(rgbImage, [1, r2, c1, r1]);
lowerRight = imcrop(rgbImage, [c2, r2, c1, r1]);
See attached for a full blown demo using MATLAB standard demo image.

David Sanchez
David Sanchez el 15 de Nov. de 2013
I = your_image;
[r c l] = size(I); % image dimensions
r2 = floor(r/2);
c2 = floor(c/2);
I1 = imcrop(I,[1 r2 1 c2];
I2 = imcrop(I,[r2+1 r 1 c2]);
I3 = imcrop(I,[1 r2 1 c2+1 c]);
I4 = imcrop(I,[r2+1 r c2+1 c]);
  1 comentario
gg
gg el 15 de Nov. de 2013
I have tried it. But there are some mistakes to implement it.
if true
% code
% I= imread('2.jpg');
% [m,n] = size(I);
%
% % I = your_image;
% [r c l] = size(I); % image dimensions
% r2 = floor(r/2);
% c2 = floor(c/2);
% tempI{1} = imcrop(I,[1 r2 1 c2]);
% tempI{2} = imcrop(I,[r2+1 r 1 c2]);
% tempI{3} = imcrop(I,[1 r2 1 c2+1 c]);
% tempI{4}= imcrop(I,[r2+1 r c2+1 c]);
% q={'a1.bmp','a2.bmp','a3.bmp','a4.bmp'};
%
% for i=1:4
% imwrite(uint8(tempI{i}),q{i},'bmp');
% end
end

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