High dimension matrix summation: a + b != b + a

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Tian
Tian el 23 de Ag. de 2021
Comentada: Tian el 23 de Ag. de 2021
I have two matrices X1 and X2. Both are 10x15x10x10 dimensions. There are three scalars: ,and .
Let i={i1,i2,i3,i4} denote the index of an element. For elements with the same index in X1 and X2, say X1(i) and X2(i), I want to compute a simple weighted sum:
+ *X1(i) + *X2(i)
Since the γ's are all scalars, I think I can do this multiplication and summation at the matrix level and get the result as a 10x15x10x10 matrix. However, when I change the order of summation, the results are also different. That is:
A = + *X1 + *X2;
B = + *X2 + *X1;
The differences in all entries of A and B sum up to 2.3856e-12. However, since this is just element-wise summation, A and B should be exactly the same.
Can someone explain what is going wrong?
I do notice that if I take out , I get the same answer... Why does adding a constant affect the final result?
Please see attached for the sample data and codes.
Thank you for your help!!

Respuesta aceptada

Wan Ji
Wan Ji el 23 de Ag. de 2021
Editada: Wan Ji el 23 de Ag. de 2021
It is a problem of machine error. If you have learned numerical analysis lessons, you will notice that big number will 'eat' small number when they are added.
a = 1;
b = eps;
for i = 1:10000
a = a+b;
end
c = a+10000*eps
c-a
Well the result is
ans =
2.220446049250313e-12
When you follow this code, error will not occur!
A = gamma0 + (gamma1*X1 + gamma2*X2);
B = gamma0 + (gamma2*X2 + gamma1*X1);
A = A(:);
B = B(:);
sum(sum(B-A))
ans =
0
This is beacuse the add operator order now is now the same for two expressions
  3 comentarios
Wan Ji
Wan Ji el 23 de Ag. de 2021
So, when you do numerical analysis, avoid adding a large number with a small number or dividing a large number by small number. The error will explode if you do so. Also, you cannot minus a number far too close to the minuend.
An example will also show why:
calculate where x=1000001, y = 1000000; (use single precision)
We use
a = sqrt(single(1000001)) - sqrt(single(1000000))
The answer is
single
4.8828125e-04
While with the following transformation
a = single(1)/(sqrt(single(1000001)) + sqrt(single(1000000)))
The answer is
a = single(1)/(sqrt(single(1000001)) + sqrt(single(1000000)))
a =
single
4.9999985e-04
The answer with double precision is
a =
4.999998750000625e-04
You can see what I mean.
Tian
Tian el 23 de Ag. de 2021
Thank you for the comments. I am very new to numerical analysis and this is great to know! My problem is to simulate results for a set of given coefficients. Some coefficients are large. To prevent errors from exploding:
(1) Are there any rule of thumbs to follow?
(2) How do we know whether the numbers are right or "exploded"?
I think I can make sure small numbers come first when I sum them...

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