How to ignore NaN in a string cell

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Daneisha Blair
Daneisha Blair el 24 de Sept. de 2021
Comentada: Sulaymon Eshkabilov el 26 de Sept. de 2021
Hi,
I have a cell array called test2 that contains some NaN and strings in each column, see attached image below.
I would like to create a loop where I can loop through test2 and ignore the NaN columns. The issue I am having is NaN characteristic is double and the if statement I created, if (cellfun(@(x) any(isnan(x)),test{i},'UniformOutput',false)), gives this error input#2 expected to be a cell array, was double instead.
Side note: i is the indices, for example i=1:1590.
Any help is very much appreciated.

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Sulaymon Eshkabilov
Sulaymon Eshkabilov el 25 de Sept. de 2021
Editada: Sulaymon Eshkabilov el 25 de Sept. de 2021
A simple answer is e.g.:
TEST = test(cellfun('isclass', test, 'char')) % All NANs removed
An alternative solution is e.g.:
test(cellfun(@(test) any(isnan(test)),test)) = []
  2 comentarios
Daneisha Blair
Daneisha Blair el 25 de Sept. de 2021
Thank you!
Sulaymon Eshkabilov
Sulaymon Eshkabilov el 26 de Sept. de 2021
Most welcome!!!

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