How to create a matrix using two arrays (x & y) and a formula that uses x & y

So if

x = [4.0:-.05:3.7]

&

y = [9;15;21;27;33;39;45]

&

z = 1.3473*152/(152+y)+(5-x)*y/(152+y)

How do I create a matrix that calculates output z at the different possible combinations of x & y?

Answer 1

[Matt J]

Use implict expansion.

x  = [4.0:-.05:3.7] ;

y = [9;15;21;27;33;39;45];

z = 1.3473*152./(152+y)+(5-x).*y./(152+y)

z = 7×7

1.3279 1.3307 1.3335 1.3363 1.3391 1.3419 1.3447 1.3161 1.3206 1.3251 1.3296 1.3341 1.3386 1.3431 1.3051 1.3112 1.3173 1.3234 1.3294 1.3355 1.3416 1.2949 1.3025 1.3100 1.3175 1.3251 1.3326 1.3402 1.2853 1.2943 1.3032 1.3121 1.3210 1.3299 1.3389 1.2764 1.2866 1.2968 1.3070 1.3172 1.3274 1.3376 1.2680 1.2794 1.2908 1.3022 1.3137 1.3251 1.3365

[Thomas Pruchinski]

This worked easy.Thanks.

Answer 2

[the cyclist]

Use the meshgrid function to create 2-dimensional grids from the x and y vectors. The first example in the documentation is very similar to what you want to do.

[Thomas Pruchinski]

Tried the mesgrid to produce 2 grides for x & y. But I when I tried to calculate z from those, it errored.

[the cyclist]

x  = [4.0:-.05:3.7] ;
y = [9;15;21;27;33;39;45];

[xx,yy] = meshgrid(x,y);

z = 1.3473*152./(152+yy)+(5-xx).*yy./(152+yy)

z = 7×7

1.3279 1.3307 1.3335 1.3363 1.3391 1.3419 1.3447 1.3161 1.3206 1.3251 1.3296 1.3341 1.3386 1.3431 1.3051 1.3112 1.3173 1.3234 1.3294 1.3355 1.3416 1.2949 1.3025 1.3100 1.3175 1.3251 1.3326 1.3402 1.2853 1.2943 1.3032 1.3121 1.3210 1.3299 1.3389 1.2764 1.2866 1.2968 1.3070 1.3172 1.3274 1.3376 1.2680 1.2794 1.2908 1.3022 1.3137 1.3251 1.3365

[the cyclist]

Guessing you used / instead of ./