How to extract elements from cell arrays and compute the mean of those elements?

Hello,

I have a 1x11 cell array. Each element in the array is 128 x 1000 matrix (see figure). How can I extract the [9 10 11 12 13 28 29 30 31 32 33 34] from each element and compute the mean of these elements, so that the resultant element will be the mean[9 10 11 12 13 28 29 30 31 32 33 34] x1000 (i.e. 1x1000) in each of the 1x11 cell array. Thanks,

Answer 1

[Rik]

By far the easiest way is to use a loop.

SubB_M1power={rand(128,3),rand(128,3)};
for n=1:numel(SubB_M1power)
    SubB_M1power{n}=mean(SubB_M1power{n},1);
end
SubB_M1power

SubB_M1power = 1×2 cell array
    {[0.5482 0.4864 0.5036]}    {[0.4972 0.5038 0.5269]}

[ET]

Thanks, I think I should rephrase my question.

What I want is to extract the [9 10 11 12 13 28 29 30 31 32 33 34] rows from the 128 rows in each (128x 1000) elements and compute the mean of those elements. The results will be 1x1000 in each of the 1 x 11 cell array.

[Rik]

That is just indexing:

rows=[9 10 11 12 13 28 29 30 31 32 33 34];

SubB_M1power{n}=mean(SubB_M1power{n}(rows),1);

[ET]

Thanks Rik, I tried the suggestion. But the output isn't right.

LFrows = [9 10 11 12 13 28 29 30 31 32 33 34];

SubB_LFR1p = cell(1,11);

for n=1:numel(SubB_R1power)

SubB_LFR1p{n} = mean(SubB_R1power{n}(LFrows), 1 );

end

SubB_LFR1p (1x11 cell array) with each element 1x12

I changed the code to :

SubB_LFR1p{n} = mean(SubB_R1power{n}(LFrows,:), 1 );

It gives the correct answer of sixe 1x1000 element in a 1x11 cell array.

[Rik]

Ah yes, excuse the typo, I was a bit too fast in posting my comment.

[ET]

Nevermind, Mr. Rik. Thank you for your help. You did solve my problem.