Finding the mean of every 24 elements of 3rd dimension of a 3d array

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I have hourly weather data from 2000-2005 for an area giving a 241x121x52608 array. I am trying to condense the data down into the daily mean and so I'm looking to maintain the 241x121 matrix which denotes the location while condensing the 52608/24 into 2192 days in total (Including leap years)
I'm sure there is a simple way to do this but I'm new to Matlab so I'm struggling to come up with a solution.
Thanks

Accepted Answer

Fangjun Jiang
Fangjun Jiang on 13 Jul 2022
Edited: Fangjun Jiang on 13 Jul 2022
Something like this. Try simple example to make sure the dimension, row, column are right.
a=ones(2,3,10);
b=mean(reshape(a,2,3,2,[]),4)
b =
b(:,:,1) = 1 1 1 1 1 1 b(:,:,2) = 1 1 1 1 1 1
  3 Comments
Liam
Liam on 13 Jul 2022
That seemed to do the trick, thanks a million! New to this so I'm learning bit by bit!

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