Index location of certain dates with find and a loop

Trying to create a simple loop that identifies the index locations where each particular date (TargetDates) matches the date in a larger array of dates (t_list)

t_list --> 1924x1 double

TargetDates --> 267x1 double

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locs= zeros(length(TargetDates),1); % initialize array of locations, size 267x1

for ii = 1:size(TargetDates,1) % for each date listed in TargetDates (1:267)

locs(ii) = find(round(t_list,6) == TargetDates(ii,1)); % find the index location where rounded t_list matches the date in TargetDates

end

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I receive the error: Unable to perform assignment because the left and right sides have a different number of elements.

I am sure it is a silly error that I am just not seeing. Thanks in advance for any advice!

Answer 1

[David Hill]

[~,idx]=ismember(TargetDates,t_list);%only provides first occurance

[Laura Szczyrba]

I need the location where all TargetDates (each date in TargetDates) match t_list, not just the first occurance, which is why I was setting up the loop!

[David Hill]

You can see without a good description and sample data set we are guessing what you want or making wrong assumptions.

Answer 2

[VBBV]

locs= zeros(length(TargetDates),length(t_list)); % change preallocated array size 

Change the preAllocated size of locs

 locs(ii,:) = find(round(t_list,6) == TargetDates(ii,1));    % find returns a vector of indices that match the condition 

As you are comparing the whole t_list with TargetDates you can do above

[Laura Szczyrba]

running:

locs= zeros(length(TargetDates),length(t_list));

for ii = 1:size(DateNumber,1)

locs(ii,:) = find(round(t_list,6) == TargetDates(ii,1));

end

Gives me the same error!

[VBBV]

for ii = 1:size(TargetDates,1)

Use the above in for loop. What is size of TargetDates?

[VBBV]

It seems you are using DateNumber