Remove NAN from cell array, and calculate the average of each column through each cell
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F Z
el 22 de Abr. de 2015
Comentada: F Z
el 23 de Abr. de 2015
I have a 1 x 17 cell array called M, with each cell containing a 16 x 27 Matrix. I need to get rid of NaN in each cell. I tried this code:
for i=1:length(M) ind = isnan(M{1}); M{i}(ind)=[]; end
But the cells are reshaped to rows (1x240) and I need the expected result to be a p*q Matrix. Once the expected result is obtained, I have to go through each cell and calculate the average of each column q Any help please?
2 comentarios
Punit
el 22 de Abr. de 2015
First of all
ind = isnan(M{1});
should be ind = isnan(M{i});
Also, try replacing M{i}(ind) = 0;
then sum(M(:,q))/length(find(~ind(:,q))) would be the average of column q
Guillaume
el 22 de Abr. de 2015
Editada: Guillaume
el 22 de Abr. de 2015
What does 'get rid of NaN' mean? Obviously, you need something in that matrix entry where the NaN is: a number, NaN, Inf or +Inf are the only possibilities.
If you remove the matrix element, then the matrix cannot be square anymore.
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Guillaume
el 22 de Abr. de 2015
As of version 2015a, mean can ignore NaNs (in earlier version you had to use nanmean in the stat toolbox).
So the simplest way to calculate the mean is with:
colmeans = cellfun(@(m) mean(m, 'omitnan'), M, 'UniformOutput', false);
celldisp(colmeans);
Even simpler, would be to just store all your matrices as a 3D matrix (of size 16 x 27 x 17) and avoid cell arrays entirely:
M = cat(3, M{:});
colmeans = mean(M, 'omitnan')
3 comentarios
Guillaume
el 22 de Abr. de 2015
A simpler version of your code would be:
T = cat(3, M{:});
colmeans = mean(T(4:9, 2:22));
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