Dimensions of matrices being concatenated are not consistent

Hello. I have a series of output A=2, B=3, C=4,D=5, E=[1;0.1;0.9]. I'm trying to put all of these output together as a row matrix, F. i.e F = [A B C D E]. But i keep getting the error 'Dimensions of matrices being concatenated are not consistent'. Is there a solution to this please?

[Rowland Ogunsola]

[Rowland Ogunsola]

Dimensions of matrices being concatenated are not consistent.

Function: gradientDescent

FileName: C:\Users\oguns\Desktop\MATLAB Projects\gradientDescent.m

LineNumber: 14

This is The error it says please... I dont seem to understand, cause in that specific line 14, the dimensions seems to be right.. m=97, and data is a 97x2 matrix.. can any one help please?

[Image Analyst]

I can't run an image. Post your script - your m-file - in a NEW question (not here in Chiamaka's 3 year old question). In the meantime, try using a semicolon to concatenate the column vector onto your scalar

X = [ones(m, 1); data(:, 1)];

This will stitch them one above the other, so if m=2:

1

1

d

d

d

Using a comma tries to stitch the data column vector to the right of a single number, so if m is 2:

1 d

1 d

d

Which won't work because all columns must have the same number of rows.

Answer 1

[Image Analyst]

Because E is a column vector, not a row vector like you're building with all the rest of the numbers, you must transpose E:

A=2
B=3
C=4
D=5
E=[1; 0.1; 0.9]
F = [A, B, C, D, E']

so now F is a row vector. Or else use semicolons and don't transpose E:

A=2
B=3
C=4
D=5
E=[1; 0.1; 0.9]
F = [A; B; C; D; E]

so now F is a column vector.

[Chiamaka Agwuegbo]

That worked. Thank you very much

Answer 2

[Suresh Lanka]

A=2

B=3

C=4

D=5

E=[1; 0.1; 0.9]

F = [A, B, C, D, E']

[Image Analyst]

Yes, exactly what I said in my first answer.

[Waqar Khan]

Sometimes inconsistence comes because your function def argu arrangments, and calling arg arrangements are not match. hope it will help too.

Answer 3

[Ayobu Id]

>> A=['a' , 'b ';'c' ,'b']

Dimensions of matrices being concatenated are not consistent.

Help

[Image Analyst]

Your Answer is not an Answer to @Chiamaka Agwuegbo.

This is an error you have because you're trying to make a character array with 3 characters in the first row (a, b, and a space), and two in the second row (c and b). If you get rid of the space it will work:

A=['a', 'b'; 'c', 'b']

A = 2×2 char array
    'ab'
    'cb'