How do you assign into a function space a variable that exists in the caller script?
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Patrick Anderson
el 17 de En. de 2018
Editada: Patrick Anderson
el 17 de En. de 2018
I have a an anonymous function that uses specific inputs. When I call the function from the caller script, I want to also pass a parameter vector into the function space. However, I can't seem to do this correctly.
I am trying this repeatedly using the "assigning" function, with various permutations of 'base' and 'caller," and can't seem to make it work.
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Steven Lord
el 17 de En. de 2018
If you try Stephen's and Walter's advice and it still doesn't work, I recommend showing a small segment of code to illustrate concretely what you're trying to do. Your original problem description was very general, so the advice we could give also could only be general. The more detailed and specific the description of the problem we have, the more focused our suggestions can be.
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Walter Roberson
el 17 de En. de 2018
Demonstration code:
function at
junk = 123;
freedo = 222;
foo = @(junk) fprintf('%d, %d\n', alter1()+junk, alter2()+junk)*0+freedo;
foo(junk)
function r = alter1
assignin('caller', 'junk', 987);
assignin('caller', 'freedo', 111);
r = 0;
function r = alter2
assignin('caller', 'junk', 456);
assignin('caller', 'freedo', 888);
r = 0;
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