How to use for loop rather than nesting if loop

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Alex
Alex el 27 de En. de 2018
Comentada: Alex el 28 de En. de 2018
I want to use this code to subtract one value from each number in the histogram when all have been selected to find the new number with zero counts. This code worked (since there are two if loops with one nested) for the first two times 1 is subtracted from cdiff, but then returns the error 'Unbalanced or unexpected parenthesis or bracket.' : %check if Cdiff is empty:
if isempty(C_diff)
fprintf('C_diff is empty (all numbers have drawn once) \n');
cdiff_counts= counts - 1;%cdiff_data_vector = reshape(data,[9,numel(data)]);
C_diff = find(cdiff_counts==0);%return vector of values with 0
fprintf('By subtracting 1 count for all numbers, the new C_diff is %d\n', C_diff);
if isempty(C_diff)
fprintf('C_diff is empty (all numbers have drawn once) \n');
cdiff_counts= cdiff_counts - 1;%cdiff_data_vector = reshape(data,[9,numel(data)]);
C_diff = find(cdiff_counts==0);%return vector of values with 0
fprintf('By subtracting 1 count for all numbers, the new C_diff is %d\n', C_diff);
end
else
fprintf('C_diff is %d\n', C_diff);%
end
Replacing the first 'if' with 'for' returns 'Unbalanced or unexpected parenthesis or bracket.'
How can I get this to occur until C_diff is no longer an empty array?
if isempty(C_diff)
fprintf('C_diff is empty (all numbers have drawn once) \n');
cdiff_counts= counts - 1;%cdiff_data_vector = reshape(data,[9,numel(data)]);
C_diff = find(cdiff_counts==0);%return vector of values with 0
fprintf('By subtracting 1 count for all numbers, the new C_diff is %d\n', C_diff);
else
fprintf('C_diff is %d\n', C_diff);%
end
Best regards,
Alex
  2 comentarios
Jan
Jan el 27 de En. de 2018
There are no "if loops" in any programming language.
Alex
Alex el 27 de En. de 2018
ok, "if statement"?

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Respuesta aceptada

Jan
Jan el 27 de En. de 2018
Editada: Jan el 27 de En. de 2018
while isempty(C_diff)
cdiff_counts = counts - 1;
C_diff = find(cdiff_counts == 0);
end
It looks like C_diff contains positive values initially, maybe only integers. Then this is more efficient:
minValue = min(counts); % [EDITED]
C_diff = find(C_diff = minValue);
  3 comentarios
Jan
Jan el 27 de En. de 2018
I had a typo in the min() call. I assume, it is much cheaper. If you provide some meaningful inputs data and the wanted result, I could even test my suggestions.
Alex
Alex el 28 de En. de 2018
Thank you! I will keep that in mind for future questions. It is not necessary, but if you are interested, here is the "counts" data for numbers 1:1:49. The number 32 should be returned.

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