MATLAB Answers

Filling NaN void in polar plot

3 views (last 30 days)
djr on 17 Oct 2018
Commented: djr on 18 Oct 2018
Hello Everyone,
I am dealing with a polar plot that is incomplete due to NaN values in the data. Please see figure 'Void polar plot.png'.
If I replace NaNs with zeros then, of course, I get the whole graph but I do not know if zero is the physically right replacement for NaNs in my problem. This is shown in figure 'Nan to 0.png'. I have also attached the variable Vq that I am plotting (NaNs are replaced with zeros).
Would it be possible to have the same (complete) polar plot with NaNs being in grey color and color bar indicating only the range of real data (excluding grey color)?
My code is as follows:
close all
% Set azimuth and radial range
AngRange = deg2rad([0 180]);
RadRange = [0 2];
% Set polar grid spacing in radial direction
RD = 0:0.5:2;
% Axis properties
axprop = {'DataAspectRatio',[1 1 1],'View', [0 90],...
'Xlim', [-2 2],'visible','off'};
% Load data
% Plot results using Math Works function for polar plot
% Add color bar
ColBar = colorbar('Location','west');
Thanks, djr


Show 3 older comments
djr on 18 Oct 2018
That worked very nice (attached plot). I still need to figure out the labeling for the azimuth axis with this circle introduced because it does not show all angles and grid lines if the graph is incomplete, but at least I covered the gap with NaNs. Thank you!
djr on 18 Oct 2018
How do I accept your answer in this comment section? :) I do not see an accept answer button.
Chad Greene
Chad Greene on 18 Oct 2018
Ah, I should know better!

Sign in to comment.

Accepted Answer

Chad Greene
Chad Greene on 18 Oct 2018
What if you draw a gray circle the size of your polar graph, then plot the polar graph on top of it?


Chad Greene
Chad Greene on 18 Oct 2018
In response to the missing grid ticks--Here's a somewhat absurd solution, but maybe it will work:
1. Plot the polar plot with NaNs set to zero. 2. Plot the gray circle. 3. Plot the polar plot with NaNs transparent.
djr on 18 Oct 2018
I'll give it a try... it's a brute force method. :)

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by