After running the code for (f ') w.r.t x , we need to draw( f ' ) w.r.t G (in X-axis) while varying n=0, 0.5, 1

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function main
Pr=1;K=1;L=-1;S=0.1;
n=input('n=');
a=linspace(0,6,100);
G=linspace(0,7,100);
solinit=bvpinit(a,G,[0 1 0 1 0 0 1]);
sol=bvp4c(@ode,@bc,solinit);
xint=a;
sxint=deval(sol,xint);
function res=bc(ya,yb,G)
res=[ya(1)-S; ya(2)-L; ya(4)+n*ya(3); ya(6)-1; yb(2)-1; yb(4); yb(6);];
end
function dydx=ode(x,y,G)
dydx=[y(2); y(3);(y(2)^2-1-y(1)*y(3)-K*y(5)-G*(1-y(2)))/(1+K);y(5);2*(y(2)*y(4)-y(1)*y(5)+K*(2*y(4)+y(3)))/(2+K);y(7);-Pr*y(1)*y(7)];
end
plot(xint,sxint([2],:),'Linewidth',2); %for f'
xlabel('\eta');
ylabel('f^\prime');
hold on
end
ERROR occurs as:
n=0
Error using bvparguments (line 108)
Error in calling BVP4C(ODEFUN,BCFUN,SOLINIT):
The derivative function ODEFUN should return a column vector of length 100.
Error in bvp4c (line 130)
bvparguments(solver_name,ode,bc,solinit,options,varargin);
Error in (line 7)
sol=bvp4c(@ode,@bc,solinit);

Respuesta aceptada

Walter Roberson
Walter Roberson el 21 de Feb. de 2019
your G is length 100. You pass it to bvpinit so matlab knows that your ode function works with 100 derivatives. but your ode only returns 7 rather than 100.
I notice that your upper bound for G is 7, the same number as the derivatives calculated . I wonder if perhaps you used linspace incorrectly .
  13 comentarios
MINATI
MINATI el 27 de Feb. de 2019
Can I run pde toolbox, means I have to learn how to run this first or what to do?
Walter Roberson
Walter Roberson el 27 de Feb. de 2019
You need the PDE Toolbox instead of what you are doing. You will have to learn how to use it.

Iniciar sesión para comentar.

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