In a randomly generated matrix how to find the position(row and column) of an element by using its value?

Ive created a 5x5 matrix using the rand() function

A=rand(5)

    0.4427    0.8173    0.8001    0.1455    0.1450
    0.1067    0.8687    0.4314    0.1361    0.8530
    0.9619    0.0844    0.9106    0.8693    0.6221
    0.0046    0.3998    0.1818    0.5797    0.3510
    0.7749    0.2599    0.2638    0.5499    0.5132
    
B=find(a==0.0844)

after i enter the above code for finding the position of that particular element, the output becomes " 0x1 empty double column vector "

Im literally a newbie to matlab software so kindly help me

Answer 1

[KSSV]

Your matrix has floating point numbers..you cannot get the value you want using like that. You should use:

tol = 10^-5 ; % tolerance 
B = find(abs(A-0.0844)<tol)

[karthikeyan vishnumohan]

Thank you so much:D