can you help me to find out whats wrong here??

% Question 6)
name = "nebras";
id = 1702227;
% calculating avregae of your id digit
S = 0;
for i = 1:length(id)
S = (S + str2num(id(i)));
end
avg = S / length(id);
% Displaying result
fprintf("Name is %s\n" , name);fprintf("Average of digits of id is %f \n" , avg);% Question 6)
name = "nebras";
id = 1702227;
% calculating avregae of your id digit
S = 0;
for i = 1:length(id)
S = (S + str2num(id(i)));
end
avg = S / length(id);
% Displaying result
fprintf("Name is %s\n" , name);fprintf("Average of digits of id is %f \n" , avg);

[Rik]

Question content deleted by Nebras Alsad:

% Question 6)
name = "nebras";
id = 1702227;
% calculating avregae of your id digit
S = 0;
for i = 1:length(id)
S = (S + str2num(id(i)));
end
avg = S / length(id);
% Displaying result
fprintf("Name is %s\n" , name);fprintf("Average of digits of id is %f \n" , avg);% Question 6)
name = "nebras";
id = 1702227;
% calculating avregae of your id digit
S = 0;
for i = 1:length(id)
S = (S + str2num(id(i)));
end
avg = S / length(id);
% Displaying result
fprintf("Name is %s\n" , name);fprintf("Average of digits of id is %f \n" , avg);

[Rena Berman]

(Answers Dev) Restored edit

Answer 1

[Rik]

If you want to do this, you will probably have to convert to a char array and then convert to a double array.

%because this is your homework I will not give a complete solution, only hints
num=1234;
num_as_txt=sprintf(___,num);
num_as_txt(1) %see what this returns
double(num_as_txt(1)) %does this return what you expect? how should you change the entire vector?

As a last note: you don't need to use a loop to calculate the average, you can simply use the mean function (and you should not use str2num, use str2double instead when you need it).

[Nebras Alsad]

i didnt get it

[Rik]

What part do you have a problem with? What don't you understand? Be specific.

[Nebras Alsad]

whats wrong with my solution

[Walter Roberson]

id = 1702227;

The result of that statement is that id becomes a scalar value and length() of a scalar is 1. id will not be stored as a vector of decimal digits [1 7 0 2 2 2 7] when you execute that statement. (It will be stored as the 64 bit binary number whose decimal representation is 4700061821015425024)

[Rik]

The solution you posted in your question tries to loop through the elements of id, but that only has a single element. Then you try to use str2num, but that doesn't work, because id is already a number, not a string (or char).

[Nebras Alsad]

okay thanks mate

[Nebras Alsad]

does the same thing with the name

[Rik]

Yes, because you made it a scalar string by using the double quotes, instead of a char array by using single quotes.

And why did you delete your question content? Are you afraid you teacher will catch you cheating? Then you should have considered that before posting your question on a public forum. This is extremely rude.