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List of IDs to matrix of indexes

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Marleen van Dijk
Marleen van Dijk el 8 de Jun. de 2020
Comentada: Marleen van Dijk el 9 de Jun. de 2020
I have a list containing numbers like lijst = [1,1,1,2,2,3,3,3,3];
Now I want to make a matrix/cell array which counts up like:
A = [1,2,3;
4,5;
6,7,8,9];
(Essentially the number in the array is equal to the row in the matrix, and the number in the matrix is equal to the index of the array)
Is there a nice way to do this?

Respuesta aceptada

madhan ravi
madhan ravi el 8 de Jun. de 2020
Editada: madhan ravi el 8 de Jun. de 2020
v = 1:numel(list);
[u,~,c] = unique(list);
Wanted = arrayfun(@(x) v(list == x), u,'un',0);
% or
Wanted = accumarray(c,v,[],@(x){x.'});
celldisp(Wanted)
  3 comentarios
Marleen van Dijk
Marleen van Dijk el 9 de Jun. de 2020
I am confused now. When I try to use the function unique(ID) my output is:
"1" "10" "11" "12" "13" "14" "15" "16" "17" "18" "19" "2" "20" "21" "22" "23" "24" "25" "26" "27" "28" "29" "3" "30" "31" "32" "33" "34" "35" "36" "37" "38" "39" "4" "40" "41" "42" "43" "44" "45" "46" "47" "48" "49" "5" "50" "6" "7" "8" "9"
Marleen van Dijk
Marleen van Dijk el 9 de Jun. de 2020
I just found out it does not work because ID consists of strings instead of doubles. Thanks for the help though!

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