List of IDs to matrix of indexes

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I have a list containing numbers like lijst = [1,1,1,2,2,3,3,3,3];
Now I want to make a matrix/cell array which counts up like:
A = [1,2,3;
4,5;
6,7,8,9];
(Essentially the number in the array is equal to the row in the matrix, and the number in the matrix is equal to the index of the array)
Is there a nice way to do this?

Accepted Answer

madhan ravi
madhan ravi on 8 Jun 2020
Edited: madhan ravi on 8 Jun 2020
v = 1:numel(list);
[u,~,c] = unique(list);
Wanted = arrayfun(@(x) v(list == x), u,'un',0);
% or
Wanted = accumarray(c,v,[],@(x){x.'});
celldisp(Wanted)
  3 Comments
Marleen van Dijk
Marleen van Dijk on 9 Jun 2020
I just found out it does not work because ID consists of strings instead of doubles. Thanks for the help though!

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