Matrix multiplied by inverse is not giving correct answer

13 visualizaciones (últimos 30 días)
Raja Dawn
Raja Dawn el 26 de Jul. de 2020
Respondida: David Goodmanson el 26 de Jul. de 2020
The inverse of a matrix multiplied by itsef should give an identity matrix but the result I get is this: [0 0 0; -4 0 0; -4 0 0]
  1 comentario
Vladimir Sovkov
Vladimir Sovkov el 26 de Jul. de 2020
Try
det(sym(a))
It is strict zero. Hence, there is no inverse matrix indeed. Matlab is quite correct here.

Iniciar sesión para comentar.

Respuestas (1)

David Goodmanson
David Goodmanson el 26 de Jul. de 2020
Matlab is telling you the answer, that the matrix (call it M) is close to singular or badly scaled (singular in this case). M has a ridiculously small condition number of 2e-18. It doesn't have an inverse, and the one it comes up with is due to numerical precision issues.
If M had an inverse, it would be impossible to have a nonzero column vector u such that M*u = 0. However,
M = [1 2 3;4 5 6;7 8 9]
M*[1; -2; 1]
ans =
0
0
0

Categorías

Más información sobre Loops and Conditional Statements en Help Center y File Exchange.

Productos


Versión

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by