how to make nxn matrix

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WonJong We
WonJong We el 14 de Abr. de 2021
Comentada: WonJong We el 15 de Abr. de 2021
I want to make nxn matrix by follweing rule
n=input
first and last is 1
how can do it?
This is the original formula.
clc;
n=input
A=(n ; n)???
  2 comentarios
Walter Roberson
Walter Roberson el 14 de Abr. de 2021
Sorry, that image is too faint to read.
WonJong We
WonJong We el 14 de Abr. de 2021
Thank you for the information.
I will change!!

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Respuesta aceptada

Walter Roberson
Walter Roberson el 14 de Abr. de 2021
n = 7
n = 7
d = ones(1,n-2)/2;
M = zeros(n,n) + diag([0,d],+1) + diag([d,0],-1);
M(1) = 1; M(end) = 1;
M
M = 7×7
1.0000 0 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0 1.0000
  9 comentarios
Walter Roberson
Walter Roberson el 15 de Abr. de 2021
n=3;
%n=input ('put your n=')
d = ones(1,n-1)/2;
M = zeros(n+1,n+1) + diag([0,d],+1) + diag([d,0],-1);
M(1) = 1; M(end) = 1;
M
M = 4×4
1.0000 0 0 0 0.5000 0 0.5000 0 0 0.5000 0 0.5000 0 0 0 1.0000
T = [sym('T0') ; sym('T',[n 1]) ]
T = 
Tvals = T;
Tvals(1) = 500;
Tvals(n+1) = 300; %Tn is at position n+1
MT = subs(M*T, T, Tvals)
MT = 
eqn = MT == T
eqn = 
sol = solve(eqn)
sol = struct with fields:
T0: [1×1 sym] T1: [1×1 sym] T2: [1×1 sym] T3: [1×1 sym]
sol.T0
ans = 
500
sol.T1
ans = 
sol.T2
ans = 
sol.T3
ans = 
300
WonJong We
WonJong We el 15 de Abr. de 2021
Thank you!

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