Calculating the point of rotation for a 2D line from frame 1 to 3

Given a line that has 3 positions

At t=0, line A has coordinates (x1,y1)= (90,220) and (x2,y2)(300,255)

At t=1, line A has translated and rotated with coordinates being (x1,y1)= (90,224) and (x2,y2)(300,252)

At t=2, another translation and rotation occurs and the line has coordinates (x1,y1)= (89,226) and (x2,y2)(302,253)

How would we go about calculating the centre of rotation from frame to frame?

Answer 1

[KSSV]

The center of rotation will be the point of intersection of perpendicular bisectors. So, you need to find the perpendicular bisector equations which are strighlines and then find the point of intersection.

You may refer the following link for an example problem: https://www.dummies.com/education/math/geometry/find-center-rotation/