Matlab: differential equation: starting conditions are wrong?
2 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Niklas Kurz
el 9 de Mayo de 2021
Comentada: Niklas Kurz
el 12 de Mayo de 2021
I solved manually: with
but if I solve it with Matlab:
syms v(t) g alpha m v0;
D = diff(v,t) == g - alpha/m*v;
c1 = v;
cond = c1(0) == v0;
S = dsolve(D,cond);
pretty(S)
I get a different solution, even if I'm sure mine is right.
I know this topic is a little vast, but maybe some of you talented people has time to investigate
0 comentarios
Respuesta aceptada
Cris LaPierre
el 9 de Mayo de 2021
Editada: Cris LaPierre
el 9 de Mayo de 2021
I'm no expert, but isn't the integral equal to
That way, the algebra works out to match the result MATLAB is giving you
syms v(t) g alpha m v0;
D = diff(v,t) == g - alpha/m*v;
cond = v(0) == v0;
S = dsolve(D,cond)
which simplifies to
1 comentario
Más respuestas (1)
Walter Roberson
el 9 de Mayo de 2021
syms v(t) g alpha m v0;
D = diff(v,t) == g - alpha/m*v;
c1 = v;
cond = c1(0) == v0;
S = dsolve(D,cond);
sum(cellfun(@(X) collect(X,[g,m,alpha]), children((collect(expand(S),g)))))
Ver también
Categorías
Más información sobre Number Theory en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!