Need to apply trapezoidal rule for double integration with an array by using the for loop

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z=(0:0.1:10);
F1= @(r1,r2)exp(-(r1.^2+r2.^2).*A).*exp(-i*B.*z.*(r1.^2+r2.^2)).*besseli(n,r1.*r2./(sig^2)).*r1.*r2;
I want to use trapezoidal numerical integration on the F1 for the variables r1 and r2 for which limits are 0 to 1, where z is a matrix. The direct command of integral2 cannot be applied due to the array function. I am stuck at first loop, where the error "Conversion to double from function handle is not possible" is showing. Please help. Thanks in advance.
for i=1:m
xi=i*h;
sumx(i)=@(r2)F1(xi);
i=i+1;
end

Respuestas (1)

Sargondjani
Sargondjani el 23 de Jun. de 2021
There are two things that need correction:
1) Remove the line i=i+1. This is what the for loop does. (also don't use "i" in general because i=sqrt(-1)))
2) The funciton handle. I will try to explain how function handles work. I have a function:
F = @(a,b,X1,X2)a*X1.^2 + b*X2.^2;
a,b are parameters. I will set them, for example a=1, b=2;
Now i want to loop over X1, given values of a, b, and X2:
a=1;
b=2;
X2 = 0.1;
h=0.001;
y = NaN(1,m);
for ii = 1:m
X1 = ii*h;
y(1,ii) = F(a,b,X1,X2);
end
Now the value of F, given a,b,X1(ii),X2 are assigned to y(ii). I hope that clarifies something.
  5 comentarios
Sargondjani
Sargondjani el 23 de Jun. de 2021
You NEED to specify the value of BOTH r1 and r2, when you want to evaluate F1. Otherwise, how should matlab know hwo to calculate the value of F1
Anyway, what i think you want to do is:
%loop over value of r1:
for ii = 1:m
r1 = ii*h
% take 1d integral for r2 (given value of r1)
f_int_r2 = @(r2)F1(r1,r2);
q(1,ii) = integral(f_int_r2,0,1);
end
Anyway, I am pretty sure you can do this with the function integral2. Just it's not clear how z comes into play... is it a 3rd variable? Or you want to know the double integral for each value of z? Then you should loop over z...

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