How can I find a faster way to calculate the transpose of a matrix?
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I have a matrix A and I want to select some columns from A to form another matrix B, and calculate the sum of each columns in B. I did this way:
B = A(:,Cols)'; Where Cols are the selected columns.
eee = sum(B);
It took more than 3 seconds to do this. I am wondering if there is a fastr way to do it.
Thanks a lot.
Rik on 28 Jun 2021
The transpose is not required. You can use the second input to sum to change dimension along which it operates.
Also, an absolute time depends on the data and the computer, so without that information, it is meaningless. If you want specific help, you should post more code so we can reproduce the behavior.