Problem 1206. Angles of the hands of a clock

Solution 2063887

Submitted on 19 Dec 2019 by Asif Newaz

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Test	Status	Code Input and Output
1	Pass	t=[7 30 15]; t_correct = [43.625 91.5]; assert(max(abs(clockHandAngDifferences(t)-t_correct))<1e-10); ds = 90 dm = 181.5000 dh = 225.1250 a = 43.6250 a = 43.6250 91.5000
2	Pass	t=[11 59 59]; t_correct = [0.0916666666666401 5.89999999999998]; assert(max(abs(clockHandAngDifferences(t)-t_correct))<1e-10); ds = 354 dm = 359.9000 dh = 359.9917 a = 0.0917 a = 0.0917 5.9000
3	Pass	t=[3 45 50]; t_correct = [-162.083333333333 -25]; assert(max(abs(clockHandAngDifferences(t)-t_correct))<1e-10); ds = 300 dm = 275 dh = 112.9167 a = -162.0833 a = -162.0833 -25.0000

Test

Status

Code Input and Output

Pass

t=[7 30 15]; t_correct = [43.625 91.5]; assert(max(abs(clockHandAngDifferences(t)-t_correct))<1e-10);

ds = 90 dm = 181.5000 dh = 225.1250 a = 43.6250 a = 43.6250 91.5000

Pass

t=[11 59 59]; t_correct = [0.0916666666666401 5.89999999999998]; assert(max(abs(clockHandAngDifferences(t)-t_correct))<1e-10);

ds = 354 dm = 359.9000 dh = 359.9917 a = 0.0917 a = 0.0917 5.9000

Pass

t=[3 45 50]; t_correct = [-162.083333333333 -25]; assert(max(abs(clockHandAngDifferences(t)-t_correct))<1e-10);

ds = 300 dm = 275 dh = 112.9167 a = -162.0833 a = -162.0833 -25.0000

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