Cody

# Problem 1678. Count consecutive 0's in between values of 1

Solution 1718390

Submitted on 31 Jan 2019 by Nikolaos Nikolaou
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### Test Suite

Test Status Code Input and Output
1   Pass
x = 1; y_correct = 0; assert(isequal(zero_count(x),y_correct))

y = 0

2   Pass
x = [0 1 0 0 0 1 0 1 1 1 0 0 0 1 0 1 1 0 0]; y_correct = [1 3 1 0 0 3 1 0 2]; assert(isequal(zero_count(x),y_correct))

t = 1 p = 1 t = 0 p = 1 0 t = 1 p = 1 0 1 t = 2 p = 1 0 1 2 t = 3 p = 1 0 1 2 3 t = 0 p = 1 0 1 2 3 0 t = 1 p = 1 0 1 2 3 0 1 t = 0 p = 1 0 1 2 3 0 1 0 t = 0 p = 1 0 1 2 3 0 1 0 0 t = 0 p = 1 0 1 2 3 0 1 0 0 0 t = 1 p = 1 0 1 2 3 0 1 0 0 0 1 t = 2 p = 1 0 1 2 3 0 1 0 0 0 1 2 t = 3 p = 1 0 1 2 3 0 1 0 0 0 1 2 3 t = 0 p = 1 0 1 2 3 0 1 0 0 0 1 2 3 0 t = 1 p = 1 0 1 2 3 0 1 0 0 0 1 2 3 0 1 t = 0 p = 1 0 1 2 3 0 1 0 0 0 1 2 3 0 1 0 t = 0 p = 1 0 1 2 3 0 1 0 0 0 1 2 3 0 1 0 0 t = 1 p = 1 0 1 2 3 0 1 0 0 0 1 2 3 0 1 0 0 1 t = 2 p = 1 0 1 2 3 0 1 0 0 0 1 2 3 0 1 0 0 1 2 s = 1 s = 1 3 s = 1 3 1 s = 1 3 1 0 s = 1 3 1 0 0 s = 1 3 1 0 0 3 s = 1 3 1 0 0 3 1 s = 1 3 1 0 0 3 1 0 y = 1 3 1 0 0 3 1 0 2

3   Pass
x = [0 0 0 0 0 0]; y_correct = 6; assert(isequal(zero_count(x),y_correct))

t = 1 p = 1 t = 2 p = 1 2 t = 3 p = 1 2 3 t = 4 p = 1 2 3 4 t = 5 p = 1 2 3 4 5 t = 6 p = 1 2 3 4 5 6 y = 6

4   Pass
x = [0 0 1 0 0 1]; y_correct = [2 2]; assert(isequal(zero_count(x),y_correct))

t = 1 p = 1 t = 2 p = 1 2 t = 0 p = 1 2 0 t = 1 p = 1 2 0 1 t = 2 p = 1 2 0 1 2 t = 0 p = 1 2 0 1 2 0 s = 2 s = 2 2 y = 2 2

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