Solution 2477813

Submitted on 5 Jun 2020 by Mateus Cruz

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1 Comment

1 Comment

Mateus Cruz on 5 Jun 2020

I do not think this exercise is correct. As one should not put frosting below the cake, the area of the cake to put frost on is the area of the circle on top of it plus the area of the "bent" rectangle on its sides. Thus:
function SA = func_frosting2(r,h)
ARectangle = pi*r*h;
ACircle = pi*r^2;
SA = ARectangle + ACircle;

I think the current solution is misleading

Test Suite

Test	Status	Code Input and Output
1	Pass	r = 3; h = 2; y_correct = 65.9734; assert(abs(func_frosting(r,h) - y_correct) < 1e-4) SA = 65.9734
2	Pass	r = 0.5; h = 0.25; y_correct = 1.5708; assert(abs(func_frosting(r,h) - y_correct) < 1e-4) SA = 1.5708

Test

Status

Code Input and Output

Pass

r = 3; h = 2; y_correct = 65.9734; assert(abs(func_frosting(r,h) - y_correct) < 1e-4)

SA = 65.9734

Pass

r = 0.5; h = 0.25; y_correct = 1.5708; assert(abs(func_frosting(r,h) - y_correct) < 1e-4)

SA = 1.5708

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Problem 44943. Calculate Amount of Cake Frosting

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Problem 44943. Calculate Amount of Cake Frosting

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