{"group":{"id":1,"name":"Community","lockable":false,"created_at":"2012-01-18T18:02:15.000Z","updated_at":"2026-05-26T00:16:20.000Z","description":"Problems submitted by members of the MATLAB Central community.","is_default":true,"created_by":161519,"badge_id":null,"featured":false,"trending":false,"solution_count_in_trending_period":0,"trending_last_calculated":"2026-05-26T00:00:00.000Z","image_id":null,"published":true,"community_created":false,"status_id":2,"is_default_group_for_player":false,"deleted_by":null,"deleted_at":null,"restored_by":null,"restored_at":null,"description_opc":null,"description_html":null,"published_at":null},"problems":[{"id":43108,"title":"How many complete pizzas","description":"x is a vector with numbers of pizza slices. A corresponding vector n indicates in how many slices the pizza slices of x were cut. How many complete pizzas do we have?\r\n\r\nExample:\r\n\r\n x = [1 3 12];\r\n n = [2 6 8];\r\n\r\nin the first column we have on slice (x=1) from a pizza cut in half (n=2) -\u003e half a pizza.\r\nin the second column we have 3 slices (x=3) from a pizza cut in 6 slices (n=6) -\u003e so half a pizza.\r\nin the third column we have 12 slices of a pizzas cut in 8 slices -\u003e1.5 slices.\r\n\r\nThis combines to 2.5 pizzas, so we have 2 complete pizzas!","description_html":"\u003cp\u003ex is a vector with numbers of pizza slices. A corresponding vector n indicates in how many slices the pizza slices of x were cut. How many complete pizzas do we have?\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre\u003e x = [1 3 12];\r\n n = [2 6 8];\u003c/pre\u003e\u003cp\u003ein the first column we have on slice (x=1) from a pizza cut in half (n=2) -\u0026gt; half a pizza.\r\nin the second column we have 3 slices (x=3) from a pizza cut in 6 slices (n=6) -\u0026gt; so half a pizza.\r\nin the third column we have 12 slices of a pizzas cut in 8 slices -\u0026gt;1.5 slices.\u003c/p\u003e\u003cp\u003eThis combines to 2.5 pizzas, so we have 2 complete pizzas!\u003c/p\u003e","function_template":"function y = completePizzas(x,n)\r\n  y = x;\r\nend","test_suite":"%%\r\n x = [1 3 12];\r\n n = [2 6 8];\r\ny_correct = 2;\r\nassert(isequal(completePizzas(x,n),y_correct))\r\n%%\r\n x = [1 3 7];\r\n n = [2 6 8];\r\ny_correct = 1;\r\nassert(isequal(completePizzas(x,n),y_correct))\r\n%%\r\n x = [2 3 12];\r\n n = [2 6 8];\r\ny_correct = 3;\r\nassert(isequal(completePizzas(x,n),y_correct))\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":0,"created_by":94929,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":48,"test_suite_updated_at":"2016-10-19T11:42:50.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2016-10-06T07:55:59.000Z","updated_at":"2026-05-29T01:26:05.000Z","published_at":"2016-10-06T07:55:59.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ex is a vector with numbers of pizza slices. A corresponding vector n indicates in how many slices the pizza slices of x were cut. How many complete pizzas do we have?\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ x = [1 3 12];\\n n = [2 6 8];]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ein the first column we have on slice (x=1) from a pizza cut in half (n=2) -\u0026gt; half a pizza. in the second column we have 3 slices (x=3) from a pizza cut in 6 slices (n=6) -\u0026gt; so half a pizza. in the third column we have 12 slices of a pizzas cut in 8 slices -\u0026gt;1.5 slices.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThis combines to 2.5 pizzas, so we have 2 complete pizzas!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":43109,"title":"How many complete pizzas (number 2)","description":"x is a vector with numbers of pizza slices. A corresponding vector n indicates in how many slices the pizza slices of x were cut and t is a vector indicating the type of pizza (e.g. 1 is a margarita, 2 is a peperoni, etc.). How many complete pizzas do we have, when we cannot join 2 different pizzas?\r\n\r\nExample:\r\n\r\n x = [1 3 12];\r\n n = [2 6 8];\r\n t = [1 2 1];\r\n\r\nin the first column we have on slice (x=1) from a pizza  margarita (t=1) cut in half (n=2) -\u003e half a pizza margarita. in the second column we have 3 slices (x=3) from a peperoni pizza (t=2) cut in 6 slices (n=6) -\u003e so half a peperoni pizza. in the third column we have 12 slices of a margarita pizzas (t=1) cut in 8 slices -\u003e1.5 slices margarita pizza.\r\n\r\nso we can combine this to 2 pizza  margaritas and 0.5 peperoni pizza. So in total we can combine 2 pizzas.","description_html":"\u003cp\u003ex is a vector with numbers of pizza slices. A corresponding vector n indicates in how many slices the pizza slices of x were cut and t is a vector indicating the type of pizza (e.g. 1 is a margarita, 2 is a peperoni, etc.). How many complete pizzas do we have, when we cannot join 2 different pizzas?\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre\u003e x = [1 3 12];\r\n n = [2 6 8];\r\n t = [1 2 1];\u003c/pre\u003e\u003cp\u003ein the first column we have on slice (x=1) from a pizza  margarita (t=1) cut in half (n=2) -\u0026gt; half a pizza margarita. in the second column we have 3 slices (x=3) from a peperoni pizza (t=2) cut in 6 slices (n=6) -\u0026gt; so half a peperoni pizza. in the third column we have 12 slices of a margarita pizzas (t=1) cut in 8 slices -\u0026gt;1.5 slices margarita pizza.\u003c/p\u003e\u003cp\u003eso we can combine this to 2 pizza  margaritas and 0.5 peperoni pizza. So in total we can combine 2 pizzas.\u003c/p\u003e","function_template":"function y = completePizzas(x,n,t)\r\n  y = x;\r\nend","test_suite":"%%%%\r\n x = [1 3 12];\r\n n = [2 6 8];\r\n t = [1 2 1];\r\ny_correct = 2;\r\nassert(isequal(completePizzas(x,n,t),y_correct))\r\n%%\r\n x = [1 3 12];\r\n n = [2 6 8];\r\n t = [1 1 1];\r\ny_correct = 2;\r\nassert(isequal(completePizzas(x,n,t),y_correct))\r\n%%\r\n x = [1 3 12];\r\n n = [2 6 8];\r\n t = [1 1 2];\r\ny_correct = 2;\r\nassert(isequal(completePizzas(x,n,t),y_correct))\r\n%%\r\n x = [1 3 12];\r\n n = [2 6 8];\r\n t = [1 2 3];\r\ny_correct = 1;\r\nassert(isequal(completePizzas(x,n,t),y_correct))\r\n%%\r\n x = [1 3 58 41 24 7 5];\r\n n = [2 6 8  50 5 4 3];\r\n t = [1 2 3  1  4 2 3];\r\ny_correct = 15;\r\nassert(isequal(completePizzas(x,n,t),y_correct))\r\n","published":true,"deleted":false,"likes_count":0,"comments_count":1,"created_by":94929,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":24,"test_suite_updated_at":"2016-10-21T17:41:02.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2016-10-06T08:13:26.000Z","updated_at":"2026-05-29T01:26:07.000Z","published_at":"2016-10-06T08:13:26.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ex is a vector with numbers of pizza slices. A corresponding vector n indicates in how many slices the pizza slices of x were cut and t is a vector indicating the type of pizza (e.g. 1 is a margarita, 2 is a peperoni, etc.). How many complete pizzas do we have, when we cannot join 2 different pizzas?\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ x = [1 3 12];\\n n = [2 6 8];\\n t = [1 2 1];]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ein the first column we have on slice (x=1) from a pizza margarita (t=1) cut in half (n=2) -\u0026gt; half a pizza margarita. in the second column we have 3 slices (x=3) from a peperoni pizza (t=2) cut in 6 slices (n=6) -\u0026gt; so half a peperoni pizza. in the third column we have 12 slices of a margarita pizzas (t=1) cut in 8 slices -\u0026gt;1.5 slices margarita pizza.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eso we can combine this to 2 pizza margaritas and 0.5 peperoni pizza. So in total we can combine 2 pizzas.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"problem_search":{"problems":[{"id":43108,"title":"How many complete pizzas","description":"x is a vector with numbers of pizza slices. A corresponding vector n indicates in how many slices the pizza slices of x were cut. How many complete pizzas do we have?\r\n\r\nExample:\r\n\r\n x = [1 3 12];\r\n n = [2 6 8];\r\n\r\nin the first column we have on slice (x=1) from a pizza cut in half (n=2) -\u003e half a pizza.\r\nin the second column we have 3 slices (x=3) from a pizza cut in 6 slices (n=6) -\u003e so half a pizza.\r\nin the third column we have 12 slices of a pizzas cut in 8 slices -\u003e1.5 slices.\r\n\r\nThis combines to 2.5 pizzas, so we have 2 complete pizzas!","description_html":"\u003cp\u003ex is a vector with numbers of pizza slices. A corresponding vector n indicates in how many slices the pizza slices of x were cut. How many complete pizzas do we have?\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre\u003e x = [1 3 12];\r\n n = [2 6 8];\u003c/pre\u003e\u003cp\u003ein the first column we have on slice (x=1) from a pizza cut in half (n=2) -\u0026gt; half a pizza.\r\nin the second column we have 3 slices (x=3) from a pizza cut in 6 slices (n=6) -\u0026gt; so half a pizza.\r\nin the third column we have 12 slices of a pizzas cut in 8 slices -\u0026gt;1.5 slices.\u003c/p\u003e\u003cp\u003eThis combines to 2.5 pizzas, so we have 2 complete pizzas!\u003c/p\u003e","function_template":"function y = completePizzas(x,n)\r\n  y = x;\r\nend","test_suite":"%%\r\n x = [1 3 12];\r\n n = [2 6 8];\r\ny_correct = 2;\r\nassert(isequal(completePizzas(x,n),y_correct))\r\n%%\r\n x = [1 3 7];\r\n n = [2 6 8];\r\ny_correct = 1;\r\nassert(isequal(completePizzas(x,n),y_correct))\r\n%%\r\n x = [2 3 12];\r\n n = [2 6 8];\r\ny_correct = 3;\r\nassert(isequal(completePizzas(x,n),y_correct))\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":0,"created_by":94929,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":48,"test_suite_updated_at":"2016-10-19T11:42:50.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2016-10-06T07:55:59.000Z","updated_at":"2026-05-29T01:26:05.000Z","published_at":"2016-10-06T07:55:59.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ex is a vector with numbers of pizza slices. A corresponding vector n indicates in how many slices the pizza slices of x were cut. How many complete pizzas do we have?\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ x = [1 3 12];\\n n = [2 6 8];]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ein the first column we have on slice (x=1) from a pizza cut in half (n=2) -\u0026gt; half a pizza. in the second column we have 3 slices (x=3) from a pizza cut in 6 slices (n=6) -\u0026gt; so half a pizza. in the third column we have 12 slices of a pizzas cut in 8 slices -\u0026gt;1.5 slices.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThis combines to 2.5 pizzas, so we have 2 complete pizzas!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":43109,"title":"How many complete pizzas (number 2)","description":"x is a vector with numbers of pizza slices. A corresponding vector n indicates in how many slices the pizza slices of x were cut and t is a vector indicating the type of pizza (e.g. 1 is a margarita, 2 is a peperoni, etc.). How many complete pizzas do we have, when we cannot join 2 different pizzas?\r\n\r\nExample:\r\n\r\n x = [1 3 12];\r\n n = [2 6 8];\r\n t = [1 2 1];\r\n\r\nin the first column we have on slice (x=1) from a pizza  margarita (t=1) cut in half (n=2) -\u003e half a pizza margarita. in the second column we have 3 slices (x=3) from a peperoni pizza (t=2) cut in 6 slices (n=6) -\u003e so half a peperoni pizza. in the third column we have 12 slices of a margarita pizzas (t=1) cut in 8 slices -\u003e1.5 slices margarita pizza.\r\n\r\nso we can combine this to 2 pizza  margaritas and 0.5 peperoni pizza. So in total we can combine 2 pizzas.","description_html":"\u003cp\u003ex is a vector with numbers of pizza slices. A corresponding vector n indicates in how many slices the pizza slices of x were cut and t is a vector indicating the type of pizza (e.g. 1 is a margarita, 2 is a peperoni, etc.). How many complete pizzas do we have, when we cannot join 2 different pizzas?\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre\u003e x = [1 3 12];\r\n n = [2 6 8];\r\n t = [1 2 1];\u003c/pre\u003e\u003cp\u003ein the first column we have on slice (x=1) from a pizza  margarita (t=1) cut in half (n=2) -\u0026gt; half a pizza margarita. in the second column we have 3 slices (x=3) from a peperoni pizza (t=2) cut in 6 slices (n=6) -\u0026gt; so half a peperoni pizza. in the third column we have 12 slices of a margarita pizzas (t=1) cut in 8 slices -\u0026gt;1.5 slices margarita pizza.\u003c/p\u003e\u003cp\u003eso we can combine this to 2 pizza  margaritas and 0.5 peperoni pizza. So in total we can combine 2 pizzas.\u003c/p\u003e","function_template":"function y = completePizzas(x,n,t)\r\n  y = x;\r\nend","test_suite":"%%%%\r\n x = [1 3 12];\r\n n = [2 6 8];\r\n t = [1 2 1];\r\ny_correct = 2;\r\nassert(isequal(completePizzas(x,n,t),y_correct))\r\n%%\r\n x = [1 3 12];\r\n n = [2 6 8];\r\n t = [1 1 1];\r\ny_correct = 2;\r\nassert(isequal(completePizzas(x,n,t),y_correct))\r\n%%\r\n x = [1 3 12];\r\n n = [2 6 8];\r\n t = [1 1 2];\r\ny_correct = 2;\r\nassert(isequal(completePizzas(x,n,t),y_correct))\r\n%%\r\n x = [1 3 12];\r\n n = [2 6 8];\r\n t = [1 2 3];\r\ny_correct = 1;\r\nassert(isequal(completePizzas(x,n,t),y_correct))\r\n%%\r\n x = [1 3 58 41 24 7 5];\r\n n = [2 6 8  50 5 4 3];\r\n t = [1 2 3  1  4 2 3];\r\ny_correct = 15;\r\nassert(isequal(completePizzas(x,n,t),y_correct))\r\n","published":true,"deleted":false,"likes_count":0,"comments_count":1,"created_by":94929,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":24,"test_suite_updated_at":"2016-10-21T17:41:02.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2016-10-06T08:13:26.000Z","updated_at":"2026-05-29T01:26:07.000Z","published_at":"2016-10-06T08:13:26.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ex is a vector with numbers of pizza slices. A corresponding vector n indicates in how many slices the pizza slices of x were cut and t is a vector indicating the type of pizza (e.g. 1 is a margarita, 2 is a peperoni, etc.). How many complete pizzas do we have, when we cannot join 2 different pizzas?\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ x = [1 3 12];\\n n = [2 6 8];\\n t = [1 2 1];]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ein the first column we have on slice (x=1) from a pizza margarita (t=1) cut in half (n=2) -\u0026gt; half a pizza margarita. in the second column we have 3 slices (x=3) from a peperoni pizza (t=2) cut in 6 slices (n=6) -\u0026gt; so half a peperoni pizza. in the third column we have 12 slices of a margarita pizzas (t=1) cut in 8 slices -\u0026gt;1.5 slices margarita pizza.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eso we can combine this to 2 pizza margaritas and 0.5 peperoni pizza. So in total we can combine 2 pizzas.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"errors":[],"facets":[[],[{"value":"easy","count":1,"selected":false},{"value":"medium","count":1,"selected":false}]],"term":"tag:\"pizzas\"","page":1,"per_page":50,"sort":"map(difficulty_value,0,0,999) asc"}}