{"group":{"id":1,"name":"Community","lockable":false,"created_at":"2012-01-18T18:02:15.000Z","updated_at":"2025-12-14T01:33:56.000Z","description":"Problems submitted by members of the MATLAB Central community.","is_default":true,"created_by":161519,"badge_id":null,"featured":false,"trending":false,"solution_count_in_trending_period":0,"trending_last_calculated":"2025-12-14T00:00:00.000Z","image_id":null,"published":true,"community_created":false,"status_id":2,"is_default_group_for_player":false,"deleted_by":null,"deleted_at":null,"restored_by":null,"restored_at":null,"description_opc":null,"description_html":null,"published_at":null},"problems":[{"id":61182,"title":"Compute the required brake torque at wheel to stop the car","description":"Brake torque defines how effectively braking force translates into wheel deceleration. Given braking force and wheel radius, determine the resulting torque applied at the wheel hub.","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.44px; min-height: 0px; white-space: normal; color: rgb(33, 33, 33); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: none; white-space: normal; \"\u003e\u003cdiv style=\"block-size: 42px; display: block; min-width: 0px; padding-block-start: 0px; padding-inline-start: 2px; padding-left: 2px; padding-top: 0px; perspective-origin: 407px 21px; transform-origin: 407px 21px; vertical-align: baseline; \"\u003e\u003cdiv style=\"font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; padding-inline-start: 0px; padding-left: 0px; perspective-origin: 383px 21px; text-align: left; transform-origin: 383px 21px; white-space-collapse: preserve; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; unicode-bidi: normal; \"\u003e\u003cspan style=\"\"\u003eBrake torque defines how effectively braking force translates into wheel deceleration. Given braking force and wheel radius, determine the resulting torque applied at the wheel hub.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003c/div\u003e\u003c/div\u003e","function_template":"function T = brakeTorque(F,r)\r\nT = 0;\r\nend\r\n","test_suite":"%%\r\nF = 3000; r = 0.3;\r\nT_correct = 900;\r\nassert(isequal(brakeTorque(F,r),T_correct))\r\n\r\n%%\r\nF = 2000; r = 0.25;\r\nT_correct = 500;\r\nassert(isequal(brakeTorque(F,r),T_correct))\r\n\r\n%%\r\nF = 0; r = 0.3;\r\nT_correct = 0;\r\nassert(isequal(brakeTorque(F,r),T_correct))\r\n\r\n","published":true,"deleted":false,"likes_count":0,"comments_count":0,"created_by":2305225,"edited_by":2305225,"edited_at":"2026-02-02T06:23:14.000Z","deleted_by":null,"deleted_at":null,"solvers_count":46,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2026-02-02T06:23:10.000Z","updated_at":"2026-04-04T03:34:26.000Z","published_at":"2026-02-02T06:23:14.000Z","restored_at":null,"restored_by":null,"spam":null,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eBrake torque defines how effectively braking force translates into wheel deceleration. Given braking force and wheel radius, determine the resulting torque applied at the wheel hub.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\",\"relationship\":null}],\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"target\":\"/matlab/document.xml\",\"relationshipId\":\"rId1\"}]}"},{"id":55555,"title":"Find the force required to support a lever","description":"Students are designing a robot that will lift a block to the equilibrium position for transport to the scoring area. They have decided to use a lever to accomplish this. The lever below is composed of a WPlb. plank of length L hinged at the far-left end. The effort force FEis applied between the fulcrum and the WL lb. load. Determine the force required to support the lever in the equilibrium position. Assume the center of gravity of the plank is at the mid-point. Round to the nearest hundreds.\r\n\r\n","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.44px; min-height: 0px; white-space: normal; color: rgb(0, 0, 0); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: none solid rgb(0, 0, 0); white-space: normal; \"\u003e\u003cdiv style=\"block-size: 308.8px; display: block; min-width: 0px; padding-block-start: 0px; padding-top: 0px; perspective-origin: 407px 154.4px; transform-origin: 407px 154.4px; vertical-align: baseline; \"\u003e\u003cdiv style=\"block-size: 105px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 52.5px; text-align: left; transform-origin: 384px 52.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eStudents are designing a robot that will lift a block to the equilibrium position for transport to the scoring area. They have decided to use a lever to accomplish this. The lever below is composed of a W\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eP\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003elb. plank of length L hinged at the far-left end. The effort force F\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eE\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eis applied between the fulcrum and the W\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eL\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e lb. load. Determine the force required to support the lever in the equilibrium position. Assume the center of gravity of the plank is at the mid-point. Round to the nearest hundreds.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 164.8px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 82.4px; text-align: left; transform-origin: 384px 82.4px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cimg class=\"imageNode\" style=\"vertical-align: baseline\" 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data-image-state=\"image-loaded\"\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 21px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 10.5px; text-align: left; transform-origin: 384px 10.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003c/div\u003e\u003c/div\u003e","function_template":"function F = findFE(L,dL,dE,wP,wL) % Do not edit this line.\r\n  % insert your code here\r\nend % Do not edit this line.\r\n\r\n","test_suite":"%%\r\nassert(isequal(findFE(100,20,70,2,5), 7.14));\r\n%%\r\nassert(isequal(findFE(200,65,125,3.5,5),8.2));\r\n%%\r\nassert(isequal(findFE(175,35,100,4.2,7),13.48));\r\n\r\n\r\n","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":542228,"edited_by":542228,"edited_at":"2022-10-11T18:26:23.000Z","deleted_by":null,"deleted_at":null,"solvers_count":234,"test_suite_updated_at":"2022-10-11T18:26:23.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2022-09-09T15:18:58.000Z","updated_at":"2026-04-03T02:10:15.000Z","published_at":"2022-09-09T15:18:58.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eStudents are designing a robot that will lift a block to the equilibrium position for transport to the scoring area. They have decided to use a lever to accomplish this. The lever below is composed of a W\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003eP\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003elb. plank of length L hinged at the far-left end. The effort force F\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003eE\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003eis applied between the fulcrum and the W\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003eL\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e lb. load. Determine the force required to support the lever in the equilibrium position. Assume the center of gravity of the plank is at the mid-point. Round to the nearest hundreds.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"159\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"315\\\"/\u003e\u003cw:attr w:name=\\\"verticalAlign\\\" w:val=\\\"baseline\\\"/\u003e\u003cw:attr w:name=\\\"altText\\\" w:val=\\\"\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId1\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc 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load on arm 1","description":"A robot is designed with a motor directly attached at the pivot point of the lifting arm.  The L inch arm has a weight of W1 lbs. that is concentrated at its center of gravity which is located at CG inches from the fulcrum. Determine the maximum weight W2 that the arm can lift if the motor provides Tq in. lbs. of torque and the load is located at the right end of the arm. Round to the nearest hundredth.\r\n","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.44px; min-height: 0px; white-space: normal; color: rgb(0, 0, 0); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: none solid rgb(0, 0, 0); white-space: normal; \"\u003e\u003cdiv style=\"block-size: 165.8px; display: block; min-width: 0px; padding-block-start: 0px; padding-top: 0px; perspective-origin: 407px 82.9px; transform-origin: 407px 82.9px; vertical-align: baseline; \"\u003e\u003cdiv style=\"block-size: 84px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 42px; text-align: left; transform-origin: 384px 42px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eA robot is designed with a motor directly attached at the pivot point of the lifting arm.\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e  \u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eThe L inch arm has a weight of W1 lbs. that is concentrated at its center of gravity which is located at CG inches from the fulcrum. Determine the maximum weight W2 that the arm can lift if the motor provides Tq in. lbs. of torque and the load is located at the right end of the arm. Round to the nearest hundredth.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 72.8px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 36.4px; text-align: left; transform-origin: 384px 36.4px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cimg class=\"imageNode\" style=\"vertical-align: baseline\" 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line.\r\n","test_suite":"%%\r\nassert(isequal(calcLoad(9.5,12,6,0.5),0.54));\r\n%%\r\nassert(isequal(calcLoad(33,15,8,1),1.67));\r\n%%\r\nassert(isequal(calcLoad(25,22,11,1.2),0.54));\r\n\r\n\r\n","published":true,"deleted":false,"likes_count":4,"comments_count":1,"created_by":542228,"edited_by":542228,"edited_at":"2022-10-11T18:20:01.000Z","deleted_by":null,"deleted_at":null,"solvers_count":311,"test_suite_updated_at":"2022-10-11T18:20:01.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2022-09-08T17:25:32.000Z","updated_at":"2026-04-03T02:04:32.000Z","published_at":"2022-09-08T17:25:32.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document 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Determine the maximum weight W2 that the arm can lift if the motor provides Tq in. lbs. of torque and the load is located at the right end of the arm. 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Find the mass of a  rod","description":"Determine the mass (in grams) of a rod of length L cm if it is in equilibrium per the diagram.  In the diagram L1, L2, L3 are distance from the left end of the rod, in the order specified (i.e, L3\u003eL2\u003eL1). Assume the center of gravity is at the midpoint of the rod. Find the mass to the nearest gram.\r\n","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.44px; min-height: 0px; white-space: normal; color: rgb(0, 0, 0); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: none solid rgb(0, 0, 0); white-space: normal; \"\u003e\u003cdiv style=\"block-size: 154.8px; display: block; min-width: 0px; padding-block-start: 0px; padding-top: 0px; perspective-origin: 407px 77.4px; transform-origin: 407px 77.4px; vertical-align: baseline; \"\u003e\u003cdiv style=\"block-size: 63px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 31.5px; text-align: left; transform-origin: 384px 31.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eDetermine the mass (in grams) of a rod of length L cm if it is in equilibrium per the diagram.\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e  \u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eIn the diagram L1, L2, L3 are distance from the left end of the rod, in the order specified (i.e, L3\u0026gt;L2\u0026gt;L1). Assume the center of gravity is at the midpoint of the rod. Find the mass to the nearest gram.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 82.8px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 41.4px; text-align: left; transform-origin: 384px 41.4px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cimg class=\"imageNode\" style=\"vertical-align: baseline\" 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410));","published":true,"deleted":false,"likes_count":4,"comments_count":1,"created_by":542228,"edited_by":542228,"edited_at":"2022-10-11T18:23:33.000Z","deleted_by":null,"deleted_at":null,"solvers_count":260,"test_suite_updated_at":"2022-10-11T18:23:33.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2022-09-09T14:54:29.000Z","updated_at":"2026-04-03T02:09:04.000Z","published_at":"2022-09-09T14:57:54.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eDetermine the mass (in grams) of a rod of length L cm if it is in equilibrium per the diagram.\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e  \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003eIn the diagram L1, L2, L3 are distance from the left end of the rod, in the order specified (i.e, L3\u0026gt;L2\u0026gt;L1). Assume the center of gravity is at the midpoint of the rod. 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of Balancing Force","description":"A box weighing W1 pounds is placed where its center of mass is located d1 ft from the fulcrum. A balancing force is placed at the opposite end of an L ft plank, d2 ft from the fulcrum. The plank has a weight of W2. Find the magnitude of the balancing force to the nearest hundredth of a pound.\r\n","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.4333px; min-height: 0px; white-space: normal; color: rgb(0, 0, 0); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: rgb(0, 0, 0); white-space: normal; \"\u003e\u003cdiv style=\"block-size: 218.5px; display: block; min-width: 0px; padding-block-start: 0px; padding-top: 0px; perspective-origin: 407px 109.25px; transform-origin: 407px 109.25px; vertical-align: baseline; \"\u003e\u003cdiv style=\"block-size: 63px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 31.5px; text-align: left; transform-origin: 384px 31.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 384px 8px; transform-origin: 384px 8px; unicode-bidi: normal; \"\u003e\u003cspan style=\"\"\u003eA box weighing W1 pounds is placed where its center of mass is located d1 ft from the fulcrum. A balancing force is placed at the opposite end of an L ft plank, d2 ft from the fulcrum. The plank has a weight of W2. Find the magnitude of the balancing force to the nearest hundredth of a pound.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 146.5px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 73.25px; text-align: left; transform-origin: 384px 73.25px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cimg class=\"imageNode\" style=\"vertical-align: baseline;width: 347px;height: 141px\" 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line.\r\n\r\n","test_suite":"%%\r\nassert(isequal(balanceforce(7,1.5,4.5,5,2),1.22));\r\n\r\n%%\r\nassert(isequal(balanceforce(2,0.2,1.5,13,5),0.07));\r\n\r\n%%\r\nassert(isequal(balanceforce(2,0.2,1.5,0,0),0));","published":true,"deleted":false,"likes_count":7,"comments_count":2,"created_by":542228,"edited_by":223089,"edited_at":"2022-10-12T10:26:17.000Z","deleted_by":null,"deleted_at":null,"solvers_count":267,"test_suite_updated_at":"2022-10-12T10:26:17.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2022-09-08T16:48:51.000Z","updated_at":"2026-04-03T03:40:29.000Z","published_at":"2022-09-08T16:48:51.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document 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A balancing force is placed at the opposite end of an L ft plank, d2 ft from the fulcrum. The plank has a weight of W2. Find the magnitude of the balancing force to the nearest hundredth of a pound.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"141\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"347\\\"/\u003e\u003cw:attr w:name=\\\"verticalAlign\\\" w:val=\\\"baseline\\\"/\u003e\u003cw:attr w:name=\\\"altText\\\" w:val=\\\"\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" 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the required brake torque at wheel to stop the car","description":"Brake torque defines how effectively braking force translates into wheel deceleration. Given braking force and wheel radius, determine the resulting torque applied at the wheel hub.","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.44px; min-height: 0px; white-space: normal; color: rgb(33, 33, 33); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: none; white-space: normal; \"\u003e\u003cdiv style=\"block-size: 42px; display: block; min-width: 0px; padding-block-start: 0px; padding-inline-start: 2px; padding-left: 2px; padding-top: 0px; perspective-origin: 407px 21px; transform-origin: 407px 21px; vertical-align: baseline; \"\u003e\u003cdiv style=\"font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; padding-inline-start: 0px; padding-left: 0px; perspective-origin: 383px 21px; text-align: left; transform-origin: 383px 21px; white-space-collapse: preserve; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; unicode-bidi: normal; \"\u003e\u003cspan style=\"\"\u003eBrake torque defines how effectively braking force translates into wheel deceleration. Given braking force and wheel radius, determine the resulting torque applied at the wheel hub.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003c/div\u003e\u003c/div\u003e","function_template":"function T = brakeTorque(F,r)\r\nT = 0;\r\nend\r\n","test_suite":"%%\r\nF = 3000; r = 0.3;\r\nT_correct = 900;\r\nassert(isequal(brakeTorque(F,r),T_correct))\r\n\r\n%%\r\nF = 2000; r = 0.25;\r\nT_correct = 500;\r\nassert(isequal(brakeTorque(F,r),T_correct))\r\n\r\n%%\r\nF = 0; r = 0.3;\r\nT_correct = 0;\r\nassert(isequal(brakeTorque(F,r),T_correct))\r\n\r\n","published":true,"deleted":false,"likes_count":0,"comments_count":0,"created_by":2305225,"edited_by":2305225,"edited_at":"2026-02-02T06:23:14.000Z","deleted_by":null,"deleted_at":null,"solvers_count":46,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2026-02-02T06:23:10.000Z","updated_at":"2026-04-04T03:34:26.000Z","published_at":"2026-02-02T06:23:14.000Z","restored_at":null,"restored_by":null,"spam":null,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eBrake torque defines how effectively braking force translates into wheel deceleration. Given braking force and wheel radius, determine the resulting torque applied at the wheel hub.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\",\"relationship\":null}],\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"target\":\"/matlab/document.xml\",\"relationshipId\":\"rId1\"}]}"},{"id":55555,"title":"Find the force required to support a lever","description":"Students are designing a robot that will lift a block to the equilibrium position for transport to the scoring area. They have decided to use a lever to accomplish this. The lever below is composed of a WPlb. plank of length L hinged at the far-left end. The effort force FEis applied between the fulcrum and the WL lb. load. Determine the force required to support the lever in the equilibrium position. Assume the center of gravity of the plank is at the mid-point. Round to the nearest hundreds.\r\n\r\n","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.44px; min-height: 0px; white-space: normal; color: rgb(0, 0, 0); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: none solid rgb(0, 0, 0); white-space: normal; \"\u003e\u003cdiv style=\"block-size: 308.8px; display: block; min-width: 0px; padding-block-start: 0px; padding-top: 0px; perspective-origin: 407px 154.4px; transform-origin: 407px 154.4px; vertical-align: baseline; \"\u003e\u003cdiv style=\"block-size: 105px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 52.5px; text-align: left; transform-origin: 384px 52.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eStudents are designing a robot that will lift a block to the equilibrium position for transport to the scoring area. They have decided to use a lever to accomplish this. The lever below is composed of a W\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eP\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003elb. plank of length L hinged at the far-left end. The effort force F\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eE\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eis applied between the fulcrum and the W\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eL\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e lb. load. Determine the force required to support the lever in the equilibrium position. Assume the center of gravity of the plank is at the mid-point. Round to the nearest hundreds.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 164.8px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 82.4px; text-align: left; transform-origin: 384px 82.4px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cimg class=\"imageNode\" style=\"vertical-align: baseline\" 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data-image-state=\"image-loaded\"\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 21px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 10.5px; text-align: left; transform-origin: 384px 10.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003c/div\u003e\u003c/div\u003e","function_template":"function F = findFE(L,dL,dE,wP,wL) % Do not edit this line.\r\n  % insert your code here\r\nend % Do not edit this line.\r\n\r\n","test_suite":"%%\r\nassert(isequal(findFE(100,20,70,2,5), 7.14));\r\n%%\r\nassert(isequal(findFE(200,65,125,3.5,5),8.2));\r\n%%\r\nassert(isequal(findFE(175,35,100,4.2,7),13.48));\r\n\r\n\r\n","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":542228,"edited_by":542228,"edited_at":"2022-10-11T18:26:23.000Z","deleted_by":null,"deleted_at":null,"solvers_count":234,"test_suite_updated_at":"2022-10-11T18:26:23.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2022-09-09T15:18:58.000Z","updated_at":"2026-04-03T02:10:15.000Z","published_at":"2022-09-09T15:18:58.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eStudents are designing a robot that will lift a block to the equilibrium position for transport to the scoring area. They have decided to use a lever to accomplish this. The lever below is composed of a W\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003eP\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003elb. plank of length L hinged at the far-left end. The effort force F\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003eE\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003eis applied between the fulcrum and the W\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003eL\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e lb. load. Determine the force required to support the lever in the equilibrium position. Assume the center of gravity of the plank is at the mid-point. Round to the nearest hundreds.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"159\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"315\\\"/\u003e\u003cw:attr w:name=\\\"verticalAlign\\\" w:val=\\\"baseline\\\"/\u003e\u003cw:attr w:name=\\\"altText\\\" w:val=\\\"\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId1\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc 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load on arm 1","description":"A robot is designed with a motor directly attached at the pivot point of the lifting arm.  The L inch arm has a weight of W1 lbs. that is concentrated at its center of gravity which is located at CG inches from the fulcrum. Determine the maximum weight W2 that the arm can lift if the motor provides Tq in. lbs. of torque and the load is located at the right end of the arm. Round to the nearest hundredth.\r\n","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.44px; min-height: 0px; white-space: normal; color: rgb(0, 0, 0); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: none solid rgb(0, 0, 0); white-space: normal; \"\u003e\u003cdiv style=\"block-size: 165.8px; display: block; min-width: 0px; padding-block-start: 0px; padding-top: 0px; perspective-origin: 407px 82.9px; transform-origin: 407px 82.9px; vertical-align: baseline; \"\u003e\u003cdiv style=\"block-size: 84px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 42px; text-align: left; transform-origin: 384px 42px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eA robot is designed with a motor directly attached at the pivot point of the lifting arm.\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e  \u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eThe L inch arm has a weight of W1 lbs. that is concentrated at its center of gravity which is located at CG inches from the fulcrum. Determine the maximum weight W2 that the arm can lift if the motor provides Tq in. lbs. of torque and the load is located at the right end of the arm. Round to the nearest hundredth.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 72.8px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 36.4px; text-align: left; transform-origin: 384px 36.4px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cimg class=\"imageNode\" style=\"vertical-align: baseline\" 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line.\r\n","test_suite":"%%\r\nassert(isequal(calcLoad(9.5,12,6,0.5),0.54));\r\n%%\r\nassert(isequal(calcLoad(33,15,8,1),1.67));\r\n%%\r\nassert(isequal(calcLoad(25,22,11,1.2),0.54));\r\n\r\n\r\n","published":true,"deleted":false,"likes_count":4,"comments_count":1,"created_by":542228,"edited_by":542228,"edited_at":"2022-10-11T18:20:01.000Z","deleted_by":null,"deleted_at":null,"solvers_count":311,"test_suite_updated_at":"2022-10-11T18:20:01.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2022-09-08T17:25:32.000Z","updated_at":"2026-04-03T02:04:32.000Z","published_at":"2022-09-08T17:25:32.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document 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Determine the maximum weight W2 that the arm can lift if the motor provides Tq in. lbs. of torque and the load is located at the right end of the arm. 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Find the mass of a  rod","description":"Determine the mass (in grams) of a rod of length L cm if it is in equilibrium per the diagram.  In the diagram L1, L2, L3 are distance from the left end of the rod, in the order specified (i.e, L3\u003eL2\u003eL1). Assume the center of gravity is at the midpoint of the rod. Find the mass to the nearest gram.\r\n","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.44px; min-height: 0px; white-space: normal; color: rgb(0, 0, 0); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: none solid rgb(0, 0, 0); white-space: normal; \"\u003e\u003cdiv style=\"block-size: 154.8px; display: block; min-width: 0px; padding-block-start: 0px; padding-top: 0px; perspective-origin: 407px 77.4px; transform-origin: 407px 77.4px; vertical-align: baseline; \"\u003e\u003cdiv style=\"block-size: 63px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 31.5px; text-align: left; transform-origin: 384px 31.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eDetermine the mass (in grams) of a rod of length L cm if it is in equilibrium per the diagram.\u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003e  \u003c/span\u003e\u003c/span\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; \"\u003e\u003cspan style=\"\"\u003eIn the diagram L1, L2, L3 are distance from the left end of the rod, in the order specified (i.e, L3\u0026gt;L2\u0026gt;L1). Assume the center of gravity is at the midpoint of the rod. Find the mass to the nearest gram.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 82.8px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 41.4px; text-align: left; transform-origin: 384px 41.4px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cimg class=\"imageNode\" style=\"vertical-align: baseline\" 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410));","published":true,"deleted":false,"likes_count":4,"comments_count":1,"created_by":542228,"edited_by":542228,"edited_at":"2022-10-11T18:23:33.000Z","deleted_by":null,"deleted_at":null,"solvers_count":260,"test_suite_updated_at":"2022-10-11T18:23:33.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2022-09-09T14:54:29.000Z","updated_at":"2026-04-03T02:09:04.000Z","published_at":"2022-09-09T14:57:54.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eDetermine the mass (in grams) of a rod of length L cm if it is in equilibrium per the diagram.\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e  \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003eIn the diagram L1, L2, L3 are distance from the left end of the rod, in the order specified (i.e, L3\u0026gt;L2\u0026gt;L1). Assume the center of gravity is at the midpoint of the rod. 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of Balancing Force","description":"A box weighing W1 pounds is placed where its center of mass is located d1 ft from the fulcrum. A balancing force is placed at the opposite end of an L ft plank, d2 ft from the fulcrum. The plank has a weight of W2. Find the magnitude of the balancing force to the nearest hundredth of a pound.\r\n","description_html":"\u003cdiv style = \"text-align: start; line-height: 20.4333px; min-height: 0px; white-space: normal; color: rgb(0, 0, 0); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: rgb(0, 0, 0); white-space: normal; \"\u003e\u003cdiv style=\"block-size: 218.5px; display: block; min-width: 0px; padding-block-start: 0px; padding-top: 0px; perspective-origin: 407px 109.25px; transform-origin: 407px 109.25px; vertical-align: baseline; \"\u003e\u003cdiv style=\"block-size: 63px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 31.5px; text-align: left; transform-origin: 384px 31.5px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cspan style=\"block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 384px 8px; transform-origin: 384px 8px; unicode-bidi: normal; \"\u003e\u003cspan style=\"\"\u003eA box weighing W1 pounds is placed where its center of mass is located d1 ft from the fulcrum. A balancing force is placed at the opposite end of an L ft plank, d2 ft from the fulcrum. The plank has a weight of W2. Find the magnitude of the balancing force to the nearest hundredth of a pound.\u003c/span\u003e\u003c/span\u003e\u003c/div\u003e\u003cdiv style=\"block-size: 146.5px; font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 73.25px; text-align: left; transform-origin: 384px 73.25px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; \"\u003e\u003cimg class=\"imageNode\" style=\"vertical-align: baseline;width: 347px;height: 141px\" 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line.\r\n\r\n","test_suite":"%%\r\nassert(isequal(balanceforce(7,1.5,4.5,5,2),1.22));\r\n\r\n%%\r\nassert(isequal(balanceforce(2,0.2,1.5,13,5),0.07));\r\n\r\n%%\r\nassert(isequal(balanceforce(2,0.2,1.5,0,0),0));","published":true,"deleted":false,"likes_count":7,"comments_count":2,"created_by":542228,"edited_by":223089,"edited_at":"2022-10-12T10:26:17.000Z","deleted_by":null,"deleted_at":null,"solvers_count":267,"test_suite_updated_at":"2022-10-12T10:26:17.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2022-09-08T16:48:51.000Z","updated_at":"2026-04-03T03:40:29.000Z","published_at":"2022-09-08T16:48:51.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document 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A balancing force is placed at the opposite end of an L ft plank, d2 ft from the fulcrum. The plank has a weight of W2. Find the magnitude of the balancing force to the nearest hundredth of a pound.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"141\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"347\\\"/\u003e\u003cw:attr w:name=\\\"verticalAlign\\\" w:val=\\\"baseline\\\"/\u003e\u003cw:attr w:name=\\\"altText\\\" w:val=\\\"\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" 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