version 1.6.0.0 (4.22 KB) by
Zachary Danziger

Calculates the Hausdorff Distance between two sets of points in a Euclidean metric space.

The Hausdorff Distance is a mathematical construct to measure the "closeness" of two sets of points that are subsets of a metric space.

Such a measure may be used to assign a scalar score to the similarity between two trajectories, data clouds or any sets of points.

This function will return the Hausdorff Distance between two sets of points.

For more information on the Hausdorff Distance: http://en.wikipedia.org/wiki/Hausdorff_distance

Zachary Danziger (2021). Hausdorff Distance (https://www.mathworks.com/matlabcentral/fileexchange/26738-hausdorff-distance), MATLAB Central File Exchange. Retrieved .

Created with
R2009a

Compatible with any release

**Inspired by:**
Hausdorff Distance

**Inspired:**
Modified Hausdorff Distance, *MEX* Modified Hausdorff Distance for 2D Point Sets

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Rohit RanadeHassan R-EsfahlanSteven Goesshirin shkMoseLeelin xinyuMu QiaoggyyreeHi Zachary，

Just a couple of quick questions:

1. Will your implementation OK with 3D data points? For example, I have got two sets of 3D data points represented by vertices (x, y, z) and (x', y', z'). Will this implementation be able to handle this?

2. I found another implementation at

http://uk.mathworks.com/matlabcentral/fileexchange/29968-modified-hausdorff-distance

However, the results given by this one are different from your implementation. Could you please comment on this?

Thanks so much for your fantastic work.

Son NguyenHi Zachary.

What I mean is that one can use the coordinate of a point to be the set. For instance, the point (1,2,3) will turn into the set {1,2,3} -- the set consisting of the coordinates.

So using that idea, I would like to see which set is a distance of d away from a point P = (a,b,c) that I input. [I only want to take points in space.]

Zachary Danziger@Son: The Hausdorff distance between two points will be the the same as the "regular" Euclidean distance. The Hausdorff distance becomes useful when you compare two sets of points.

Son NguyenHi.

I am new to Matlab. Can someone assist me on how to use this program?

Basically what I would like to do is I want to put in a point in space, say (0,0,0), and specify the maximum distance, say 5. I would like to find all points in space whose Hausdorff distance to the origin is at most 5.

Thank you for your time.

Reza AhmadzadehAll the warnings could be avoided by adding comma between the output arguments. [a b] --> [a,b].

Zachary Danziger@Duc Fehr Thanks for the input, this could be really useful. I haven't worked with with parallelizing MATLAB computations very much.

Duc FehrVery nice piece of code. I am wondering if this change is possible: l91-l110, making use of the parallel computation. I realize that sometimes a vector of length sP(1) or sQ(1) might still be too big too save, but there is a big difference between a matrix of size sP(1)*sQ(1) and a vector those individual length.

minP = zeros(1,sP(1));

parfor p = 1:sP(1)

% calculate the minimum distance from points in P to Q

minP(p) = min(sum( bsxfun(@minus,P(p,:),Q).^2, 2));

end

maxP = max(minP);

% repeat for points in Q

minQ = zeros(1,sQ(1));

parfor q = 1:sQ(1)

minQ(q) = min(sum( bsxfun(@minus,Q(q,:),P).^2, 2));

end

maxQ = max(minQ);

wangi want calculate Hausdorff distance between two index images!!!

siwar chnitiplease I need a code to calculate Hausdorff distance between two binary images!!!

Zachary Danziger@Yunus, Your question is a bit ambiguous. As written, the code will interpret your input sets as having one 2-dimensional point each, in which case we do expect a non-zero HD because the points are different, and in fact, are different precisely by their Euclidean distance. If you are interested in comparing sets with two 1-dimensional points each you need to transpose your inputs. Rows are treated as observations and columns as dimensions.

hd = HausdorffDist([1 2],[2 1]) -> 1.41

hd = HausdorffDist([1 2]',[2 1]') -> 0

Yunus EmreVery useful code indeed. I have a question :

Assume that we have two sets, i.e {1,2} and {2,1}. The Hausdorff distance between these two sets are zero. However, in the code we got the value of Euclidean distance between points. Am I wrong?

Zachary Danziger@Shaan, One way would be to treat those images as vectors of pixels, and use the code on those vectors, however, many more nuanced implementations of HD for image comparison have been developed.

ShaanHow do you use this code to calculate Hausdorff distance between two binary images?

Pasha MahmoudzadehIt is great code, but you need to fix your bugs: in order to achieve the same column for your both images, you can fix number of columns with the following codes:

nrows = max(size(I1,1), size(I2,1));

ncols = max(size(I1,2), size(I2,2));

nchannels = size(I1,3);

extendedI1 = [ I1, zeros(size(I1,1), ncols-size(I1,2), nchannels); ...

zeros(nrows-size(I1,1), ncols, nchannels)];

extendedI2 = [ I2, zeros(size(I2,1), ncols-size(I2,2), nchannels); ...

zeros(nrows-size(I2,1), ncols, nchannels)];

I1=extendedI1;

I2=extendedI2;

Also, Binary images don't give us the minimum numbers for Hausdorff Distance. I checked your codes with several binary images and all of the times the max Hausdorff Distance numbers were the correct answer, not the minimum number.

Venkat RVery fast and useful submission.

Works well for me. Thank you

Pramit MazumdarHi,

I am having two vectors consisting of sequential locations visited by person-X and Y like:

X = [ (lat1,long1), (lat2,long2), (lat3,long3) ];

Y = [ (lat4,long4), (lat2,long2), (lat3,long3) ];

I need to find similarity between these two vectors. Can this Hausdorff distance help me in any way??

Nejc IlcZachary DanzigerRoel H,

Agreed on both counts. The code has been updated and re-posted. Doing some quick testing, the updates you recommended significantly improve speed for very large matrices, thank you.

Roel HNice code, thanks for writing this function!

Though I have a few remarks. For the largeMat case, it is better to use bsxfun instead of repmat, as it is more efficient(faster) for large matrices which obviously is the case. Also it may be an idea to postpone the "sqrt" call untill a maximum is found. This won't change the outcome, but should require less computations

%existing code:

minP = min(sqrt(sum((repmat(P(p,:),[sQ(1) 1]) - Q).^2,2)));

%sugestion:

minP = min(sum((bsxfun(@minus,P(p,:),Q)).^2,2));

Zachary DanzigerIt was brought to my attention by Roey Baror of Tel-Aviv University that creating/outputting a matrix of distances between all points could quickly tax the system's memory for large matrices, such as high resolution images. The update provides a secondary algorithm to calculate the Hausdorff Distance without storing the large matrix in memory, and detects automatically when this secondary algorithm is necessary.

s_ppulonganSasikanthNice code and well commented to!