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Adam


1.877 total contributions since 2014

Professional Interests: Signal Processing, OOP, Matlab GUI programming, Machine Learning

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Answered
Store only 4 value from a loop
If you have a nested loop like that you would generally want something like x(t,i) = ... with a 2d output to match the 2 neste...

alrededor de 3 horas ago | 0

Answered
Detecting change in sign of values of a column
NewC = find( diff( sign( Data(:,2) ) ) ) + 1;

alrededor de 24 horas ago | 1

| accepted

Answered
How to reshape a matrix into nx2 matrix?
reshape( A( :, [ 1:2:end, 2:2:end ] ), [], 2 ) You may wish to change the final two arguments to the reshape command in diffe...

12 días ago | 0

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Answered
Unable to use a value of type cell as an index
You are passing in a variable called title to the second function. This will hide the function of the same name so that this in...

12 días ago | 1

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Answered
Assining fixed color for zero value
Define a colourmap of size n, assuming n is not huge, and then add black to the front of it n = 7; colourmap = [0 0 0; parula(...

15 días ago | 0

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Answered
Any way to use British spellings for function calls and arguments?
https://blogs.mathworks.com/loren/2016/04/01/the-queens-matlab/ I took this seriously at first and was appalled! Not because I...

19 días ago | 2

Answered
Matlab data classes advantages
https://uk.mathworks.com/help/matlab/matlab_prog/fundamental-matlab-classes.html In basic terms obviously floating point (doubl...

20 días ago | 0

Answered
How to concatenate 2 cell arrays containing strings?
vertcat( x{:} )

20 días ago | 0

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Answered
Why do I need to declare a variable inside a nested 'for' loop?
You are referring to it on the right-hand side of the equation as well as on the left. First time round it does not exist yet s...

22 días ago | 1

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Answered
signal processing (segmentation in time domain)
sig1 = sig( t >= 0.34 && t <= 4 ); sig2 = sig( t >= 6 && t <= 8.5 ); If you also need the t vector then apply it similarly. J...

22 días ago | 0

Answered
finding inverse exponential value
If i and j are pixel values then you must have an image to which they are applied, e.g. im, in which case simply exp( -im(i,j) ...

22 días ago | 0

Answered
Reference to non-existent field error
exist('handles.mystructdata') does not work for struct fields. isfield( handles, 'mystructdata' ) is what you should use to c...

26 días ago | 1

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Answered
How to replace values of certain rows in a matrix?
a( [2 3], : ) = repmat( b, 2, 1 ) A bit more generally: indicesToReplace = [2 3]; a( [2 3], : ) = repmat( b, indicesToReplace...

26 días ago | 0

Answered
FFT step by step help
The lpad part is a little suspicious. If you have an odd length of signal it will not work as is. Apart from that though: xdf...

27 días ago | 1

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Answered
Index exceeds the number of array elements
[A, index] = unique (A); replaces what was in A with the result of unique (i.e. all the non-unique values removed) So indexing...

27 días ago | 0

Answered
Get position when using uicontextmenu
I use code like this to position my context menu under the cursor on an axes, though if you already have the figure handle at th...

29 días ago | 0

Answered
replace duplicate value by 0 in matrix or vector
[C,ia] = unique( b ); b( setdiff( 1:numel(b), ia ) ) = 0;

29 días ago | 1

Answered
Unrecognized function or variable 'axes34_CreateFcn'.
Unless you have explicitly created one axes don't have a createFcn set by default, so I assume you must have asked it to create ...

30 días ago | 0

Answered
disp function error in matlab coder
disp is not supported by Coder. sprintf should work though.

alrededor de 1 mes ago | 0

Answered
How to create empty matrix in matlab?
myMatrix = cell( 10 ); would create a 10x10 cell array. If all your images are the same size though you'd be better off with t...

alrededor de 1 mes ago | 0

Answered
How can I display a specific frame in my image series ?
image10 = allImages( :, :, 10 ); images2_5 = double( allImages( :, : [2 5] ) ); image2_minusImage5 = diff( images2_5, [], 3 );...

alrededor de 1 mes ago | 0

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Answered
extract logical locations that match array
B .* A would seem to give what you want

alrededor de 1 mes ago | 0

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Answered
how to select the desired range of each dimension from the 3d array?
new_precipitation = precipitation( 1400:1439, 500:519, 700:900 ) would create what you ask for though it will be 1 bigger in ea...

alrededor de 1 mes ago | 0

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Answered
Convert Z dimension to X dimension
myArray(:) will do for that kind of reshape, where myArray is obviously the array you start with.

alrededor de 1 mes ago | 0

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Answered
Initial centroids selection - Kmeans
doc kmeans shows the idx = kmeans(X,k,Name,Value) function signature. If you look at the options for 'Name', 'Value' pairs y...

alrededor de 2 meses ago | 0

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Answered
MATLAB Answers Wish-list #5 (and bug reports)
Has there been any further thought on changing what is considered a compulsory field for users asking a question? Title, body a...

alrededor de 2 meses ago | 2

Answered
How to define range using a variable in xlsread?
doc sprintf can create a string out of variables, e.g. columnStr = 'B'; startRow = 50; endRow = 50; sprintf( '%s%i:EHI%i', ...

alrededor de 2 meses ago | 0

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Answered
SOM codebook vectors output
net.IW{1} will give you the codebook vectors/weights. For example: x = simplecluster_dataset; net = selforgmap([8 8]); net ...

alrededor de 2 meses ago | 0

Answered
How to automatically put the asked values in function by script?
You would have to define a function that takes two arguments (or an array of inputs to add), e.g. for an example of a fixed two ...

alrededor de 2 meses ago | 0

Answered
Dimensions of arrays being concatenated are not consistent.
Results_Values=[Amp',N',T',[velocity NaN].'];

alrededor de 2 meses ago | 1

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