Respondida
Accessing multiple fields in nested structures for string comparison
Assuming libinfo is a scalar structure, and hence libinfo.Raithinfo is a cell array, you may benefit from using cellfun (or arra...
Accessing multiple fields in nested structures for string comparison
Assuming libinfo is a scalar structure, and hence libinfo.Raithinfo is a cell array, you may benefit from using cellfun (or arra...
alrededor de 8 años hace | 1
| aceptada
Respondida
How to create an array containing all possible combinations of 0's and 1's to length n
n = 3 c = arrayfun(@(k) mat2cell(dec2bin(0:2^k-1)-'0', ones(2^k,1), k), 1:n, 'un', 0) c = vertcat(c{:})
How to create an array containing all possible combinations of 0's and 1's to length n
n = 3 c = arrayfun(@(k) mat2cell(dec2bin(0:2^k-1)-'0', ones(2^k,1), k), 1:n, 'un', 0) c = vertcat(c{:})
alrededor de 8 años hace | 0
Respondida
Can I use unique to reduce one row, but keep reference to how many cells it was reduced from?
You are looking for some run-length encoding scheme: A = [ 1 1.5 2 2.5 3 3.5 4 4.5 5 10 10 10 20 20 3...
Can I use unique to reduce one row, but keep reference to how many cells it was reduced from?
You are looking for some run-length encoding scheme: A = [ 1 1.5 2 2.5 3 3.5 4 4.5 5 10 10 10 20 20 3...
alrededor de 8 años hace | 0
Enviada
allcomb(varargin)
All combinations of input (v4.2, apr 2018)
alrededor de 8 años hace | 4 descargas |
Enviada
isfunction(FUN)
returns true for valid matlab functions (v3.2, apr 2018)
más de 8 años hace | 2 descargas |
Respondida
I try to optimalize a temperature when looking at different concentrations for a chemical reaction. I get a good plot for values of k from 1 tot 70 but when going higher it won't work anymore. I don't know what to do, anyone?
You should reset t(1) to zero before the inner loop. You might not even need a vector t. Just use t = t + tstep, as you only use...
I try to optimalize a temperature when looking at different concentrations for a chemical reaction. I get a good plot for values of k from 1 tot 70 but when going higher it won't work anymore. I don't know what to do, anyone?
You should reset t(1) to zero before the inner loop. You might not even need a vector t. Just use t = t + tstep, as you only use...
más de 8 años hace | 0
Respondida
How does the for-cycle check its conditions?
You cannot change the parameters of the for-loop within the counter, as demonstrated here: a = 2 ; b = 6 ; c = 0 ; fo...
How does the for-cycle check its conditions?
You cannot change the parameters of the for-loop within the counter, as demonstrated here: a = 2 ; b = 6 ; c = 0 ; fo...
más de 8 años hace | 1
Respondida
Find length of a structure element and remove them according to length?
L = arrayfun(@(k) numel(output(k).I), 1:numel(output)) output(L > 100) = [] ; % remove those elements of the structure arra...
Find length of a structure element and remove them according to length?
L = arrayfun(@(k) numel(output(k).I), 1:numel(output)) output(L > 100) = [] ; % remove those elements of the structure arra...
más de 8 años hace | 1
| aceptada
Respondida
I want to know the cell number i.e. row and column of the matrix, whichever is above 10% of the normal vlaue. and i also want to get the values in the cell.
I am unsure if I understand your question completely, but here is my 2p: X = rand(4,3) % example data TF = X > 0.1 ...
I want to know the cell number i.e. row and column of the matrix, whichever is above 10% of the normal vlaue. and i also want to get the values in the cell.
I am unsure if I understand your question completely, but here is my 2p: X = rand(4,3) % example data TF = X > 0.1 ...
más de 8 años hace | 0
Respondida
Is it possible to do this without for cycle?
% data Y = [1 1 3 2 3 1 1 2] % M = numel(Y) K = 3 % engine T = double((Y(:) - (1:K))==0)
Is it possible to do this without for cycle?
% data Y = [1 1 3 2 3 1 1 2] % M = numel(Y) K = 3 % engine T = double((Y(:) - (1:K))==0)
más de 8 años hace | 0
| aceptada
Enviada
nextperm(V, K)
Next (lexicographic) permutation of values
más de 8 años hace | 2 descargas |
Respondida
Add zeros to matrices same as length of another matrix
To pad an matrix A with zeros to match a larger or same-sized array B, you can use this: A = magic(3) B = ones(3, 5) ...
Add zeros to matrices same as length of another matrix
To pad an matrix A with zeros to match a larger or same-sized array B, you can use this: A = magic(3) B = ones(3, 5) ...
más de 8 años hace | 0
Respondida
how do I convert a cell array of different size cells to a matrix
An easy job for padcat :) c = {{1 2}; {1 2 3};{4 5 6};{10 11 12 12 14}} % rather awkward cell array of cell arrays of n...
how do I convert a cell array of different size cells to a matrix
An easy job for padcat :) c = {{1 2}; {1 2 3};{4 5 6};{10 11 12 12 14}} % rather awkward cell array of cell arrays of n...
más de 8 años hace | 0
Respondida
How to convert string to number and process underscores? (e.g. '57_77_' to 57.77)
all in one go: a = '12_23_' v = str2num(strrep(a(1:end-1), '_', '.'))
How to convert string to number and process underscores? (e.g. '57_77_' to 57.77)
all in one go: a = '12_23_' v = str2num(strrep(a(1:end-1), '_', '.'))
más de 8 años hace | 1
Respondida
hi everybody , i'm a beginner and don't know how can i convert ascii to a string
A = [51 48 56 ; 73 48 71] str = char(A) % conversion from ascii to character string
hi everybody , i'm a beginner and don't know how can i convert ascii to a string
A = [51 48 56 ; 73 48 71] str = char(A) % conversion from ascii to character string
más de 8 años hace | 0
| aceptada
Respondida
find max value within set parameters of matrix
If you want to mask out elements of a vector for finding the max, without disrupting the location within the vector, you might c...
find max value within set parameters of matrix
If you want to mask out elements of a vector for finding the max, without disrupting the location within the vector, you might c...
más de 8 años hace | 1
Respondida
Array indexing for moving IQR
When N (= number of elements in A) and K (= number of elements to use) are not too large you could create an intermediate (N-K+1...
Array indexing for moving IQR
When N (= number of elements in A) and K (= number of elements to use) are not too large you could create an intermediate (N-K+1...
más de 8 años hace | 0
Respondida
Split a matrix at specific row
Use *mat2cell*: M = randi(20, 105,4) ; V = [11 12 11 11 12 12 13 11 12] ; C = mat2cell(M, V , size(M,2)) ;
Split a matrix at specific row
Use *mat2cell*: M = randi(20, 105,4) ; V = [11 12 11 11 12 12 13 11 12] ; C = mat2cell(M, V , size(M,2)) ;
más de 8 años hace | 0
| aceptada
Respondida
How to find minimal distance between elements?
Without creating a possibly large intermediate N-ny-N matrix or using a possibly slow sort V = [1 8 6 4 2 10] ; W = ncho...
How to find minimal distance between elements?
Without creating a possibly large intermediate N-ny-N matrix or using a possibly slow sort V = [1 8 6 4 2 10] ; W = ncho...
más de 8 años hace | 2
Respondida
How to find minimal distance between elements?
By definition the minimum distance is zero because v(i)==v(i) for any element i of the vector v. But I assume you want the mi...
How to find minimal distance between elements?
By definition the minimum distance is zero because v(i)==v(i) for any element i of the vector v. But I assume you want the mi...
más de 8 años hace | 0
Respondida
assign values from logial vector to a new matrix with the same size
function B = functionA(A) B = A B(~(A>0)) = 0
assign values from logial vector to a new matrix with the same size
function B = functionA(A) B = A B(~(A>0)) = 0
más de 8 años hace | 0
Respondida
Compare segments of a vector
A = [2 2 2 2 2 3 6 3 4 5 1 1 1 1 1 2 3 4 5 6] AA = reshape(A,5,[]) dA = diff(AA,[],2) ix = all(dA>0) ix = 2*fin...
Compare segments of a vector
A = [2 2 2 2 2 3 6 3 4 5 1 1 1 1 1 2 3 4 5 6] AA = reshape(A,5,[]) dA = diff(AA,[],2) ix = all(dA>0) ix = 2*fin...
más de 8 años hace | 0
Respondida
Structs fields indexing issue
Parent.Child1.field_1 = [1 2 2 3] ; Parent.Child2.field_1 = [1 3 3 2 3 2] ; Parent.Child3.field_1 = [2] ; A = str...
Structs fields indexing issue
Parent.Child1.field_1 = [1 2 2 3] ; Parent.Child2.field_1 = [1 3 3 2 3 2] ; Parent.Child3.field_1 = [2] ; A = str...
más de 8 años hace | 0
Respondida
How to choose all other indices than ones I know?
Here are two options a = [11 12 13 14 15] i = [2 3] b1 = nan(size(a)) b1(i) = a(i) b2 = a i2 = setdi...
How to choose all other indices than ones I know?
Here are two options a = [11 12 13 14 15] i = [2 3] b1 = nan(size(a)) b1(i) = a(i) b2 = a i2 = setdi...
más de 8 años hace | 1
Respondida
Average distance of nonzero diagonal to the main diagonal for sparse matrix
In your example, you do not need to check the diagonals at all, just the first row and column of the matrix! A = [0 5 0 1 ...
Average distance of nonzero diagonal to the main diagonal for sparse matrix
In your example, you do not need to check the diagonals at all, just the first row and column of the matrix! A = [0 5 0 1 ...
más de 8 años hace | 0
| aceptada
Respondida
Average distance of nonzero diagonal to the main diagonal for sparse matrix
Use the second argument of diag? A = sparse(cumsum(triu(ones(5)),2)) diag(A,1)
Average distance of nonzero diagonal to the main diagonal for sparse matrix
Use the second argument of diag? A = sparse(cumsum(triu(ones(5)),2)) diag(A,1)
más de 8 años hace | 0
Respondida
How to Return two Matrix of dimension (T,N)
function [G, H] = MyInput(T,N) % do not name this function input, as this is already used by ML !!! G = zeros(T,N) ; % p...
How to Return two Matrix of dimension (T,N)
function [G, H] = MyInput(T,N) % do not name this function input, as this is already used by ML !!! G = zeros(T,N) ; % p...
más de 8 años hace | 1
| aceptada
Respondida
How to find sampling rate from a signal vector and a time vector?
The sampling rate is the number of samples collected per second. In most typical cases, this is (roughly) a fixed (single) value...
How to find sampling rate from a signal vector and a time vector?
The sampling rate is the number of samples collected per second. In most typical cases, this is (roughly) a fixed (single) value...
más de 8 años hace | 3