What does 'li' mean?
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Hello all,
I have solved an equation in matlab using the following code:
syms x
ththa2 = (2*exp(5*x))/(3*exp(2*x)+1*exp(-2*x))
y = diff(ththa2)
eqn = y == 0
S = solve(eqn)
The answer is
S =
log(-(7^(1/2)*1i)/3)/2
log((7^(1/2)*1i)/3)/2
Would you please tell me what does this '1i' mean in the answer? What kind of a value is this?
Thank you,
Mohi
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Respuestas (3)
Image Analyst
el 20 de Oct. de 2021
It's i, the square root of -1, the imaginary constant.
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James Tursa
el 20 de Oct. de 2021
Editada: James Tursa
el 20 de Oct. de 2021
1i is used to ensure it isn't confused with a variable named i that you might have in the workspace. I.e., 1i is always sqrt(-1), whereas just i might be sqrt(-1) or a variable that you created named i. It is common to see 1i used in MATLAB for sqrt(-1) because it is always unambiguous.
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