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shiv gaur
shiv gaur el 11 de En. de 2022
Respondida: Walter Roberson el 11 de En. de 2022
function metal3
theta1=linspace(10,70,20);
%T3=1e-9:1e-9:1e-6;
for j=1:numel(theta1)
theta=theta1(j);
p0 = 0.5;
p1 = 1;
p2 = 1.5;
TOL = 10^-8;
N0 = 100;
format long;
h1 = p1 - p0;
h2 = p2 - p1;
DELTA1 = (f(p1,theta) - f(p0,theta))/h1;
DELTA2 = (f(p2,theta) - f(p1,theta))/h2;
d = (DELTA2 - DELTA1)/(h2 + h1);
i=3;
while i <= N0
b = DELTA2 + h2*d;
D = (b^2 - 4*f(p2,theta)*d)^(1/2);
if abs(b-D) < abs(b+D)
E = b + D;
else
E = b - D;
end
h = -2*f(p2,theta)/E;
p = p2 + h;
if abs(h) < TOL
p
disp(p)
break
end
p0 = p1;
p1 = p2;
p2 = p;
h1 = p1 - p0;
h2 = p2 - p1;
DELTA1 = (f(p1,theta) - f(p0,theta))/h1;
DELTA2 = (f(p2,theta) - f(p1,theta))/h2;
d = (DELTA2 - DELTA1)/(h2 + h1);
i = i + 1;
end
if i > N0
formatSpec = string('The method failed after N0 iterations,N0= %d \n');
end
P(j)=real(p);
end
plot(theta ,r)
end
function y=f(x,theta)
k0=(2*pi/0.6328)*1e6;
n0=1.3707;
n1=1.30;
n2=1.59;
n3=0.065+4*1i;
n4=3.48;
na=1.36;
t1=2.10e-6;
t2=0.198e-6;
t3=1e-6;
t4=0.002e-6;
x=n0*k0*sin(theta);
k1=k0*sqrt(n1.^2-x.^2);
k2=k0*sqrt(n2.^2-x.^2);
k3=k0*sqrt(n3.^2-x.^2);
k4=k0*sqrt(n4.^2-x.^2);
m11= cos(t1*k1)*cos(t2*k2)-(k2/k1)*sin(t1*k1)*sin(t2*k2);
m12=(1/k2)*(cos(t1*k1)*sin(t2*k2)*1i) +(1/k1)*(cos(t2*k2)*sin(t1*k1)*1i);
m21= (k1)*cos(t2*k2)*sin(t1*k1)*1i +(k2)*cos(t1*k1)*sin(t2*k2)*1i;
m22=cos(t1*k1)*cos(t2*k2)-(k1/k2)*sin(t1*k1)*sin(t2*k2);
m34= cos(t3*k3)*cos(t4*k4)-(k4/k3)*sin(t3*k3)*sin(t4*k4);
m32=(1/k4)*(cos(t3*k3)*sin(t4*k4)*1i) +(1/k3)*(cos(t4*k4)*sin(t3*k3)*1i);
m23= (k3)*cos(t4*k4)*sin(t3*k3)*1i +(k4)*cos(t3*k3)*sin(t4*k4)*1i;
m33=cos(t3*k3)*cos(t4*k4)-(k3/k4)*sin(t3*k3)*sin(t4*k4);
M11=m11*m34+m12*m23;
M12=m11*m32+m12*m33;
M21=m21*m34+m22*m23;
M22=m21*m32+m22*m33;
g0=sqrt(x.^2-n0.^2)*k0;
ga= sqrt(x.^2-na.^2)*k0;
y=(na^2*g0*M11-n0^2*ga*M22+g0*ga*M12-na^2*n0^2*M21)/(na^2*g0*M11+n0^2*ga*M22+g0*ga*M12+na^2*n0^2*M21);
r=y.^2;
end
  2 comentarios
shiv gaur
shiv gaur el 11 de En. de 2022
pl help to plot between theta vs r
shiv gaur
shiv gaur el 11 de En. de 2022
not working

Iniciar sesión para comentar.

Respuestas (1)

Walter Roberson
Walter Roberson el 11 de En. de 2022
You have
function y=f(x,theta)
You are passing in a variable named x
k0=(2*pi/0.6328)*1e6;
That's a value in the millions
n0=1.3707;
n1=1.30;
That's a value near 1
n2=1.59;
n3=0.065+4*1i;
n4=3.48;
na=1.36;
t1=2.10e-6;
t2=0.198e-6;
t3=1e-6;
t4=0.002e-6;
x=n0*k0*sin(theta);
You have not used the x that you passed in. Instead you have overwritten x with a value that is determined in part by k0, which is in the millions, so x is going to end up in the millions.
k1=k0*sqrt(n1.^2-x.^2);
Remember n1 is near 1, and you are subtracting a million squared, and taking the square root. So you are going to end up with a value that is roughly complex 1 million.
m11= cos(t1*k1)*cos(t2*k2)-(k2/k1)*sin(t1*k1)*sin(t2*k2);
cos of complex 1 million is infinite . Remember that cos of an imaginary number has to do with exponentials .

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