Index exceeds the number of array elements

>> run_LE_FO_a

p_step =

1.499999999999999e-03

Index exceeds the number of array elements. Index must not exceed 1.

Error in LE_RF_a (line 5)

X= [x(5), x(9), x(13), x(17);

Error in FDE12>f_vectorfield (line 300)

f = feval(Probl.fdefun,t,y,Probl.param) ;

Error in FDE12 (line 114)

f_temp = f_vectorfield(t0,y0(:,1),Probl) ;

Error in FO_Lyapunov_a (line 22)

[T,Y] = FDE12(q,ext_fcn,t,t+h_norm,[0 0 1 1],h,a);

Error in run_LE_FO_a (line 16)

lp=FO_Lyapunov_a(ne,ext_fcn,0,0.2,1,[0 0 1 1],0.2,1,a)

>>

fde12 only work on 3 dimensional? if you want to work on 4 dimensional where i have to change

Answer 1

[Neelanshu]

Hi Rohini,

I understand that you are facing issue when working on 4-dimensional vector as input argument in ‘FDE12.m’.

I have debugged the code and found that while using 4 dimensions, in 'LE_RF_a.m' you are accessing 5th 6th 7th elements etc which is the cause of error, as shown below:

Also refer to line 114 in 'FDE12', it should be like shown below as y0 is a row vector

f_temp = f_vectorfield(t0,y0(1,:),Probl) ;

instead of

f_temp = f_vectorfield(t0,y0(:,1),Probl) ;

Hope it helps,

Regards,

Neelanshu