How can return the maximum appearance number in the square matrix?
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Salem
el 26 de Feb. de 2015
Comentada: Salem
el 28 de Feb. de 2015
How can I find the most repeated number in nxn matrice? For example, if I have 3x3 matrix like this [1 2 3; 6 6 4; 4 7 6] In this case the most repeated number is 6. But if two or more numbers have repeated same time I want to retrieve the biggest one like next example [2 5 2; 7 8 4; 5 -1 0] In this case I want the function return the 5 because it is greater than 2 which both have the same number of appearances in the matrix. I appreciate your help in advance
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Sad Grad Student
el 26 de Feb. de 2015
Editada: Sad Grad Student
el 26 de Feb. de 2015
It's easy.. I have a feeling you're trying to get us to do your assignment... ;)
Hint: Lookup:
You're welcome! :)
Respuesta aceptada
per isakson
el 27 de Feb. de 2015
Editada: per isakson
el 27 de Feb. de 2015
"most repeated number in nxn matrice"
M = [1 2 3; 6 6 4; 4 7 6];
binranges = [min(M(:)):max(M(:))];
[num,ix] = max( histc( M(:), binranges ) )
val = binranges(ix)
the value, val, is repeated num times.
 
"retrieve the biggest one" the above code will retrieve the smallest
M = [1 2 3; 6 6 4; 4 7 6];
binranges = [min(M(:)):max(M(:))];
bincounts = histc( M(:), binranges );
[num,ix] = max( fliplr( bincounts ) );
val = binranges(ix)
I've not tested this
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