Creating a function similar to a sawtooth function

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John Carroll
John Carroll el 26 de Oct. de 2022
Comentada: John Carroll el 27 de Oct. de 2022
Hello
I am trying to create a function similar to the sawtooth function. I would like a simple set of commands that would create a 1xn matrix of values based on the input of a maximum number and step size. For example I'd like to give the input of 20 for the maximum and a step size of 5 and receiver a matrix of the following form.
[0 5 10 15 20 15 10 5 0 -5 -10 -15 -20 -15 -10 -5 0]
The sawtooth function seems to create something similar but I was hoping someone could seggest another way that could produce the matrix as I am showing.
Thank you

Respuesta aceptada

Voss
Voss el 26 de Oct. de 2022
n = 17;
max_val = 20;
step_val = 5;
m = max_val/step_val;
temp = step_val*[0:m m-1:-1:-m -m+1:-1];
result = repmat(temp,1,ceil(n/numel(temp)));
result = result(1:n)
result = 1×17
0 5 10 15 20 15 10 5 0 -5 -10 -15 -20 -15 -10 -5 0
  4 comentarios
Les Beckham
Les Beckham el 27 de Oct. de 2022
FWIW, here is another approach where you specify the number of cycles instead of the number of data points.
n = 5; % number of cycles
max_val = 20;
step_val = 5;
temp = 0:step_val:max_val;
result = [repmat([temp(1:end-1) flip(temp(2:end))], 1, n) 0];
plot(result)
grid on
John Carroll
John Carroll el 27 de Oct. de 2022
I'm going to try this one as well and see if it rans any better in my code. Thanks.

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