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Solving Integral in matlab

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SHAMA NOREEN
SHAMA NOREEN el 17 de Abr. de 2023
Editada: Torsten el 17 de Abr. de 2023
I need to solve this integral in matlab
Where a=1, b=0.71, c=0.53.
I have tried this in matlab
syms s
a=1;
b=0.71;
c=0.53;
f = 1/((s+a^2)*sqrt(((s+a)^2)*((s+b)^2)*((s+c)^2)));
F = int(f, 0, inf)
but I am unable to solve the problem

Respuestas (2)

Dyuman Joshi
Dyuman Joshi el 17 de Abr. de 2023
Editada: Dyuman Joshi el 17 de Abr. de 2023
There are cases when int is unable to compute the value of definite integral. In such cases, use vpa to obtain the approximate numerical value
syms s
a = 1;
b = 0.71;
c = 0.53;
f = 1/((s+a^2)*sqrt(((s+a)^2)*((s+b)^2)*((s+c)^2)));
F = int(f, 0, inf);
val1 = vpa(F)
val1 = 
0.67917589608295134074024322188586
You can use vpaintegral directly as well -
val2 = vpaintegral(f,0,inf)
val2 = 
0.679176

Torsten
Torsten el 17 de Abr. de 2023
Editada: Torsten el 17 de Abr. de 2023
syms s
a=sym('1');
b=sym('71/100');
c=sym('53/100');
f = 1/((s+a^2)*(s+a)*(s+b)*(s+c));
F = a*b*c/2*int(f)
F = 
limit(F-subs(F,s,0),s,Inf)
ans = 

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