How to change date in a for loop?
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Punit Gandhi
el 9 de Abr. de 2015
Comentada: Punit Gandhi
el 9 de Abr. de 2015
I am working in a for loop and inside the loop it looks as follows:
format shortg
c=clock;
display(c);
c_fc = c+[0 0 0 4 0 0]; %addition for weather forecast in hours or days
%only if 4 hour forecast is being done. change the parameters
%(date or hours)accordingly
if c(4)< 20;
c_fc(4)=c_fc(4);
else if c(4)==20;
c_fc(4)=0;
c_fc(3)=c_fc(3)+1;
else if c(4)== 21;
c_fc(4)=1;
c_fc(3)=c_fc(3)+1;
else if c(4)==22;
c_fc(4)=2;
c_fc(3)=c_fc(3)+1;
else if c(4)==23;
c_fc(4)=3;
c_fc(3)=c_fc(3)+1;
end
end
end
end
end
%making a search query for real time and forecast data
search=sprintf('%d-%0.2d-%0.2dT%0.2d:00:00Z',c(1:4));
search_fc=sprintf('%d-%0.2d-%0.2dT%0.02d:00:00Z',c_fc(1:4));
I need to make a search_fc which takes the values from weather website for that time period. I could update the hours and date with if and else if loop. but how can I make it shorter and also incorporate change in month and year so that my code can keep on running.
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Kelly Kearney
el 9 de Abr. de 2015
Not quite sure I understand the question, but you can definitely simplify that code significantly. If I understand it correctly, c_fc is simply a datevector 4 hours after c, right? So then,
c = clock;
fcspan = 4/24; % 4 hours, converted to days
c_fc = datevec(datenum(c) + fcspan);
That will take care of any complications with changing days, and you can change the forecast span and start date however you want.
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