Borrar filtros
Borrar filtros

How do I generate numbers from an Exponential Distribution within Min and Max values?

4 visualizaciones (últimos 30 días)
How to generate random numbers with the exponential distribution applied, and also given a minimum value of 0.5, and a maximum value of 4.3, the mean is 1.5?
How do I add the maximum to the following?
pd = makedist('Exponential','mu', 1.5);
r=0;
while r<0.5
r=random(pd);
end

Respuesta aceptada

Star Strider
Star Strider el 11 de Jul. de 2023
Use the truncate function —
pd = makedist('Exponential','mu', 1.5);
t = truncate(pd, 0.5, 4.3);
r = random(t,10000,1);
figure
histogram(r,100)
.
  2 comentarios
John D'Errico
John D'Errico el 11 de Jul. de 2023
Editada: John D'Errico el 11 de Jul. de 2023
+1. Truncate is the correct solution, of course. It will sometimes be vastly more efficient compared to rejection schemes too, since random does not need to throw away a significant fraction of the generated samples.

Iniciar sesión para comentar.

Más respuestas (2)

Vishnu
Vishnu el 11 de Jul. de 2023
Hi Sean Sarran,
Simply insert a "or" statement in the while loop condition itself to apply a maximum value of 4.3.
Consequently, this is the whole code:
pd = makedist('Exponential', 'mu', 1.5);
r = 0;
while r < 0.5 || r > 4.3
r = random(pd);
end

Torsten
Torsten el 11 de Jul. de 2023
pd = makedist('Exponential','mu', 1.5);
n = 100;
lb = 0.5;
ub = 4.3;
rv = zeros(n,1);
i = 0;
while i < n
r = random(pd);
if r >= lb & r <= ub
i = i+1;
rv(i) = r;
end
end
rv
rv = 100×1
3.7779 1.5435 0.8186 2.5542 3.0388 2.1058 1.9611 1.3722 0.9059 3.2783

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by