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Having problems with integration equations.

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Thomas
Thomas el 10 de Dic. de 2023
Respondida: Sulaymon Eshkabilov el 10 de Dic. de 2023
syms t
v_1 = 90/(1+0.3*t);
d_1 = int(v_1,t);
a_1 = diff(v_1,t);
pretty(d_1)
pretty(v_1)
pretty(a_1)
In this code the d_1 value is incorrect
d_2 = 300*log(1+0.3*t);
v_2 = diff(d_2,t);
a_2 = diff(v_2,t);
pretty(d_2)
pretty(v_2)
pretty(a_2)
syms t
The above code uses the correct integral of 'v_1' (verified by hand) and differentiates accordingly with both the 'v' and 'a' equations being the same across both segments of code

Respuestas (1)

Sulaymon Eshkabilov
Sulaymon Eshkabilov el 10 de Dic. de 2023
Hi Thomas,
Actually, all calcs are correct - see:
syms t
v_1 = 90/(1+0.3*t);
d_1 = int(v_1,t)
d_1 = 
% Here d_1 is verified
Ver = diff(d_1, t)
Ver = 
Verified = (300*(3/10))/((3/10)*(t+10/3)) % Numerator and Denominator is multiplied by (3/10)
Verified = 
v_1 % Compare with the given
v_1 = 
[Verified v_1]
ans = 

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