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Generating data for a scheduling problem that deals with setup families.

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clc
%clear all
x1 = 1:30;
x11 = 1:10;
x2 = 0.2:0.2:1;
x12 = 0.2:0.2:4;
%a = 6:100;%b = 125:25:1000;%c = 1050:50:2500;%cc = 3000:500:10000;%cc1 = 15000:5000:30000;%xx = [a b c cc cc1];%[A, B] = size(xx);%mx = max(xx);
n=input('n=');
data = cell(n, 10, 3);
%families = 1:6;
familiesNumber = [2, 4, 6];
familiesSetup = 1:6;
for F = 1:3
% for j = 1:B
% n = xx(j);
% for ex = 1:10
releaseDate = randsrc(1, n, x1);
processingTime = randsrc(1, n, x11);
tf = randsrc(1, 1, x12);
ddr = randsrc(1, 1, x2);
g = sum(releaseDate);
min_due = tf * (1 - g - ddr / 2);
max_due = tf * (1 - g + ddr / 2);
if min_due < 1, min_due = 1; end % Ensure minimum due date is at least 1
if max_due < min_due, max_due = min_due + 1; end % Ensure range is valid
x = min_due:max_due;%linspace(min_due, max_due, n); % Create a range with n points
dueDate = randsrc(1, n, x); % Generate dueDate within the range
% Ensure dueDate is valid
for i = 1:n
if dueDate(i) < processingTime(i)
dueDate(i) = processingTime(i) + 1;
end
end
f = familiesNumber(F); disp(f);
m = mod(n, f);
nn = n - m;
setupTime = zeros(1, f);
for s = 1:f
setupTime = familiesSetup;
end
disp(setupTime);
nf = zeros(1, f);
if m == 0
for i = 1:f
nf(i) = n / f;
end
else
for i = 1:m
nf(i) = (nn / f) + 1;
end
for ii = m+1:f
nf(ii) = (nn / f);
end
end
disp(nf);
da = [releaseDate; processingTime; dueDate]; %disp(da);
data{n, ex, f} = da;
% end
% end
end
savefile = 'a_data.mat';
save(savefile, 'data');
  3 comentarios
alaa sabah
alaa sabah el 6 de Jul. de 2024
Thank you for your responses, I have a scheduling problem to solve, considering setup families, a number of jobs distributing on (2,4,6) families where every family must has one setup time, I need the right generating data code. If you can code it, be generouse and give me a help.
Walter Roberson
Walter Roberson el 6 de Jul. de 2024
I need the right generating data code
That sounds more like an algorithm question than a question about MATLAB ?

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