Discrepancy with d2c function?
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
den = [(Me*c1) (Me*k1) (c1*(k1+k2)) (k1*k2)];
num = [(c1*N) (k1*N)];
sys1 = tf(num,den);
sys1d = c2d(sys1,0.001);
When I run the above piece of code and then use d2c on sys1d, I get my original transfer function sys1. However, if I copy the num and den fieds in sys1d, create a discrete transfer function from it and use d2c, it does not give me the original sys1. I am stumped as to why. Any help will be highly appreciated.
Thanks
0 comentarios
Respuestas (1)
Andrew Schenk
el 19 de Jun. de 2015
The following code does what you are describing and is able to exactly recover the original sys1. It is better to use the tfdata function instead of copying the num and den fields as the full precision is then preserved.
sys1 = tf([1 -1],[1 4 5]);
sys1d = c2d(sys1,0.001);
[num, den] = tfdata(sys1d); %extract discrete tf num and den fields
sys2d = tf(num, den, 0.001);
sys2 = d2c(sys2d)
0 comentarios
Ver también
Categorías
Más información sobre Oil, Gas & Petrochemical en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!