Overloaded inbuilt operators causing maximum recursion errors
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JMP Phillips
el 17 de Dic. de 2015
Comentada: JMP Phillips
el 21 de Dic. de 2015
I am trying to do overloaded inbuilt operators, such as overloading == (eq) for A == B (or eq(A,B)).
I did this: In my working directory I created a new folder 'overloads' , within that directory created a folder @double, and then the function eq.m which is my overloaded function:
function [result] = eq(A,B)
if abs(A-B)<1e-12
result = 1;
else
result = 0;
end
This seems to work fine. The problem is I am getting weird behavior after creating this overloaded function. For example whenever I subtract two numbers in the command line, such as 4-5, or 2 - 3 (any numbers really), I get this error: "maximum recursion limit of 500 reached... etc'. Whenever I try to use any operators, even ones I have not overloaded, I get this weird behavior .
Any ideas?
6 comentarios
Adam
el 21 de Dic. de 2015
Your code will also say two numbers with difference smaller than 1e-12 are equal even if those numbers themselves are of that order of magnitude and are percentage-wise very different, but I guess if you never work with small numbers and you are happy to accept any consequences of Matlab's algorithms also using your definition of equality that is 'ok'
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Walter Roberson
el 17 de Dic. de 2015
function [result] = eq(A,B)
result = abs(A-B)<1e-12);
end
Notice this returns logical not double. In your code the double 0 and double 1 you returned would have had to have been compared against 0 by MATLAB in order to try to figure out whether the value you had returned was true or false.
I recommend, by the way, that you specifically comment how your code will deal with NaN and with vectors or arrays and with comparing values of different size()
I also recommend that you consider making the tolerance a relative tolerance based upon eps.
5 comentarios
Adam
el 17 de Dic. de 2015
In addition to Guillaume's comment, Matlab uses its operators within many of its own other builtin functions so if you overload them you can easily end up with your overloaded function being called in all sorts of places you don't expect rather than just the ones you explicitly use yourself.
Walter Roberson
el 17 de Dic. de 2015
Editada: Walter Roberson
el 18 de Dic. de 2015
When you overload an existing class operator you are not making any explicit references, you are messing with ALL use of the operator (except for nested functions in the original implementation, those take local precedence.) Overloading is nearly unscoped.
But the poster did not ask us if this was a good idea, or ask us how to confine the effects to particular routines. The poster has already gone as far as to keep the power supply on while opening the cover of the No User Serviceable Parts section, and I am okay with them finding out experimentally what can go wrong.
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