Why is the ODE solver saying not enough input arguments?
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Mohannad Abboushi
el 28 de Feb. de 2016
Editada: Mohannad Abboushi
el 28 de Feb. de 2016
In this program I am modeling the cell cycle with three differential equations. I am trying to output all three variables C, M and X to a graph, but I am missing something. Here's the code:
function Cellcycle= Cellcycle (~,~,~,~,~,~,~,~,~,~,~,~,~,~,~,~,~,~,~)
K1 = 0.005;
K2 = 0.005;
K3 = 0.005;
K4 = 0.005;
Kc = 0.5;
Kd = 0.02;
kd = 0.01;
V2 = 1.5;
V4 = 0.5;
vd = 0.25;
VM1 = 3;
VM3 = 1;
C = 0.01;
M = 0.01;
X = 0.01;
dC= 0.025-vd*X*(C/(Kd+C)) - kd*C;
dM = VM1*(C/(Kc+C))*((1-M)/(K1+(1-M))) - V2*(M/(K2+M));
dX = M*VM3*((1-X)/(K3+(1-X))) - V4*(X/(K4+X));
Cellcycle= [dC dM dX];
[~,~,~,~,~,~,~,~,~,~,~,~,~,~,~,~] = ode45('Cellcycle',ode45,[0 10],[.01 .01 .01]);
plot(dC,dM,dX);
end
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Respuesta aceptada
Walter Roberson
el 28 de Feb. de 2016
Note that you are ignoring the ode inputs, so your calls are always going to return the same thing, with a rather boring output as a result. I have taken the liberty of guessing what you are trying to do and changing the code appropriately
function Cellcycle_driver
[t,y] = ode45(@Cellcycle, [0 10], [.01 .01 .01]);
dC = y(:,1);
dM = y(:,2);
dX = y(:,3);
plot(t, dC, 'g', t, dM, 'b', t, dX, 'r');
legend({'dC', 'dM', 'dX'});
function dy = Cellcycle(t, y)
K1 = 0.005;
K2 = 0.005;
K3 = 0.005;
K4 = 0.005;
Kc = 0.5;
Kd = 0.02;
kd = 0.01;
V2 = 1.5;
V4 = 0.5;
vd = 0.25;
VM1 = 3;
VM3 = 1;
% C = 0.01;
% M = 0.01;
% X = 0.01;
C = y(1):
M = y(2);
X = y(3);
dC= 0.025-vd*X*(C/(Kd+C)) - kd*C;
dM = VM1*(C/(Kc+C))*((1-M)/(K1+(1-M))) - V2*(M/(K2+M));
dX = M*VM3*((1-X)/(K3+(1-X))) - V4*(X/(K4+X));
dy = [dC; dM; dX];
1 comentario
Mohannad Abboushi
el 28 de Feb. de 2016
Editada: Mohannad Abboushi
el 28 de Feb. de 2016
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