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imshow border tight for subplot

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Sukuchha
Sukuchha el 10 de Feb. de 2012
Editada: Erik el 8 de Oct. de 2013
i can hide the grey border around the figure with setting;
iptsetpref('ImshowBorder','tight');
figure;Image = rand(1000,1000);
imshow(Image,[]), colormap jet;
How can i do the same if i am using subplot! iptsetpref doesnot seem to have any effect in subplot.
iptsetpref('ImshowBorder','tight');
figure;
subplot(1,2,1)
imshow(Image,[]), colormap jet;
subplot(1,2,2)
imshow(Image,[]), colormap jet;
  2 comentarios
Sukuchha
Sukuchha el 10 de Feb. de 2012
i tried to format code, but some how it is not working !
Sukuchha
Sukuchha el 10 de Feb. de 2012
anyone?

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Respuesta aceptada

Sean de Wolski
Sean de Wolski el 10 de Feb. de 2012
Use subplott to generate axes handles for each individual subplot
h = subplott(3,3);
imshow('cameraman.tif','parent',h(6));
imshow('pout.tif','parent',h(2));
Note, the images will not be tight in both dimensions unless the figure is turned into the correct shape manually and all images are the same shape.
E.g.:
set(gcf,'units','pix')
set(gcf,'position',[200 200 800 800])
With the figure from above. Where subplott.m is:
function [hA] = subplott(nr,nc)
%function to return a figure handle and axes handles for tight subplots
%
%Inputs:
% r: number of rows
% c: number of columns
%
%Outputs:
% hA: axes handles to subplots (styled order, i.e. rows first then columns)
%
%See Also: subplot imshow
%
%Error Checking:
assert(nargin==2,'2 inputs expected');
assert(isscalar(nr)&&isscalar(nc));
%Other Constants:
rspan = 1./nr; %row span normalized units
cspan = 1./nc; %not the tv channel
na = nr*nc; %num axes
%Engine
rlow = flipud(cumsum(rspan(ones(nr,1)))-rspan); %lower edge
clow = cumsum(cspan(ones(nc,1)))-cspan;
[rg cg] = meshgrid(1:nr,1:nc); %grids
hA = zeros(na,1);
figure;
for ii = 1:na
pos = [clow(cg(ii)) rlow(rg(ii)) cspan rspan]; %positions
hA(ii) = axes('units','norm','outerposition',pos,'position',pos); %build axes
end
end
  1 comentario
Sukuchha
Sukuchha el 10 de Feb. de 2012
thanxs heap ! Thats just awesome!

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Más respuestas (1)

Sean de Wolski
Sean de Wolski el 10 de Feb. de 2012
Instead of using subplot, build the axes directly:
figure('units','pixels','position',[200 200 800 400]); 5fig
axes('units','norm','outerposition',[0 0 0.5 1],'position',[0 0 0.5 1]) %left axes
imshow(rand(100),[])
axes('units','norm','outerposition',[0.5 0 0.5 1],'position',[0.5 0 0.5 1]) %right axes
imshow(imread('cameraman.tif'),[])
  2 comentarios
Sukuchha
Sukuchha el 10 de Feb. de 2012
thanks Sean, it works wonderfully for two axes ! But i have around 12 axes, i dont want to write outerposition and position vector individually to each axes.
lets say i create a figure with
figure('units','normalized','outerposition',[0 0 1 1]);
is there a way to generate those outerposition and position vector for any arbitary division N.
Sean de Wolski
Sean de Wolski el 10 de Feb. de 2012
Sure! In fact that sounds like a good idea for a game of code golf! I'll get back to you on this later this afternoon.

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