Getting error Operands to the || and && operators must be convertible to logical scalar values.
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Astrik
el 31 de Ag. de 2016
Comentada: Param Siddharth
el 23 de Abr. de 2020
I have to check the arguments of my function for a number of cases. The function passes all tests besides the arguments
12, 3, [3 4], 5
The code is as follows
function dd= day_diff(month1, day1, month2, day2)
if month1<1 || month2<1 || day1<=0|| day2<=0 || rem(month1,1)~=0 ||rem(day1,1)~=0 || rem(month2,1)~=0 || rem(day2,1)~=0 || isscalar(month1)~=1 || isscalar(month2)~=1 || isscalar(day1)~=1 || isscalar(day2)~=1
dd=-1;
elseif (month1==2 && day1==29) || (month2==2 && day2==29)
dd=-1;
elseif (eomday(2015,month1)==30 && day1==31) ||(eomday(2015,month2)==30 && day2==31)
dd=-1;
The error I get
>> day_diff(12, 3, [3 4], 5)
Operands to the || and && operators must be convertible to logical
scalar values.
Error in day_diff (line 2)
if (month1<1 || isscalar(month1)~=1) || (month2<1
||isscalar(month1)~=1) || day1<=0|| day2<=0 || rem(month1,1)~=0
||rem(day1,1)~=0 || rem(month2,1)~=0 || rem(day2,1)~=0 ||
isscalar(day1)~=1 || isscalar(day2)~=1
Any help will be appreciated.
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Respuesta aceptada
Star Strider
el 31 de Ag. de 2016
The short-circuit operators don’t work with vector arguments. Replace them with single ‘|’ and ‘&’ and see if that solves the problem.
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Más respuestas (1)
Steven Lord
el 31 de Ag. de 2016
month2 = [3 4];
z = month2 < 1
Is z a logical scalar value? In order to be a logical scalar value, it must be BOTH logical (check this with the class function) AND scalar (check with isscalar.)
Reorder your error checking to check that the input are scalar first. Once you know your inputs are scalar, then you can check their values.
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