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Random number time series

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Bdayz
Bdayz el 13 de Sept. de 2016
Comentada: Bdayz el 13 de Sept. de 2016
Hi All,
I will like to generate Independent normally distributed data with linearly
increasing mean from say 2 to 4 and constant standard deviation, say 1.
Thank you.

Respuesta aceptada

s.p4m
s.p4m el 13 de Sept. de 2016
Editada: s.p4m el 13 de Sept. de 2016
ln = 100; % length of timeseries
Ts = 1; % timestep
for k = 1:ln
tmp_mean = 2+2*(k-1)/(ln-1); % your linearly increasing mean
tmp_devi = 1; % your constant standard deviation
x(k,1) = random('norm',tmp_mean,tmp_devi,1,1);
end
timeseries = iddata(x,[],Ts);
  1 comentario
Bdayz
Bdayz el 13 de Sept. de 2016
Thanks very much. works perfectly

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