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Undefined function or variable 'y'.

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Leandro  Cavalheiro
Leandro Cavalheiro el 23 de Oct. de 2016
Comentada: Steven Lord el 23 de Oct. de 2016
I'm trying to compute sin(x) with the nth order of the Taylor Series around a = 0; The function is
function [y] = TaylorSeries(n,x)
for i = 0:n
y = y + ((-1)^i * x^(2*i + 1))/(factorial(2*i + 1));
end
end
I'm getting -> Undefined function or variable 'y'.
Error in TaylorSeries (line 4) y = y + ((-1)^i * x^(2*i + 1))/(factorial(2*i + 1));
What's wrong? I can't seem to get on well with Matlab.

Respuestas (1)

Steven Lord
Steven Lord el 23 de Oct. de 2016
You're trying to use the value of the variable y on the line of code inside your for loop, but you haven't yet defined that variable. Because of this MATLAB doesn't know what value you want to use, and so it complains by throwing an error. Add this line before your loop to define/initialize that variable. That way MATLAB knows to use the value y = 0 on the first iteration of the loop.
y = 0;
  2 comentarios
Leandro  Cavalheiro
Leandro Cavalheiro el 23 de Oct. de 2016
I'd tried it before and got this:
>> TaylorSeries(7,pi/2)
g =
0
k =
1
Output argument "y" (and maybe others) not assigned during call to "factorial".
Error in TaylorSeries (line 5)
y = y + ((-1)^i * x^(2*i + 1))/(factorial(2*i + 1));
Steven Lord
Steven Lord el 23 de Oct. de 2016
That suggests that you've written your own factorial function (rather than use the factorial function included in MATLAB) but that there is at least one code path through it that doesn't define the output argument. My suspicion is that when you call factorial(1) it doesn't assign a value to the output.
If your homework assignment (I'm assuming this is part of a homework assignment) permits it, I recommend using the factorial function in MATLAB rather than writing your own.

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