How to replace zeros in one matrix with another matrix
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Hello, how to replace zeros in one matrix with another matrix using if statement? Dimensions are the same; first matrix has 10 zeros and second matrix has 10 numbers. Thanks for answers J
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Geoff Hayes
el 19 de Dic. de 2016
J's answer moved here
Matrix B=[1 0 0 0 0;2 3 0 0 0;4 5 6 0 0;7 8 9 10 0;11 12 13 14 15] You can see that "triu" of matrix B is made of zeros. I need to replace zeros in matrix B using IF statement with matrix A=[1 2 3 4 5;6 7 8 9 10]. Orientation is set and number of zeros is matching matrix A.
Guillaume
el 19 de Dic. de 2016
The first option in my answer matches this scenario. if is not needed.
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Andrei Bobrov
el 19 de Dic. de 2016
A = [1:3, 0,0 7,12,0]';% your first array
B = randi(20,8,1); % your second array
t = A == 0;
A(t) = B(t);
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Guillaume
el 19 de Dic. de 2016
An example would clarify what you want. Possibly:
To replace all zero values in A by consecutive values in B, B must have as many elements as there are zeros in A:
assert(numel(B) == numel(A == 0)); %B must have as many elements as there are zeros in A
A(A == 0) = B %replace zeros values in A by values in B
or to replace zeros values in A by values in B in the same position, B must be the same size as A:
assert(isequal(size(B), size(A)));
A(A == 0) = B(A == 0)
An if is most likely not needed.
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arwa
el 19 de Dic. de 2016
x = [0 0 0 0 0 0 0 0 0 0]; z = [1 2 3 4 5 6 7 8 9 10]; for i=1:1:10 x(1:i)=z(1:i); end
then you can get x = [1 2 3 4 5 6 7 8 9 10] like z instead of zeros..
Do you mean this??
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