How to replace the diagonal elements of a matrix with 0 fro avoiding self loops?
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SUNANNA S S
el 19 de Abr. de 2017
Comentada: tommsch
el 28 de Jun. de 2024 a las 8:33
I have a matrix
M= 1 0 0 0 1 0
0 1 0 1 0 0
0 0 1 0 1 1
1 0 0 1 0 0
1 1 1 0 0 0
0 0 0 1 0 1
I want to replace all the diagonal elements in this matrix to 0 if it is 1.
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Ramtin Nazerian
el 21 de Dic. de 2022
Out = M.*-(eye(height(M))-1);
This will make all the diagonal values of your matrix zero as long as the matrix is square. hope that helps :).
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Stephen23
el 19 de Abr. de 2017
Editada: Stephen23
el 19 de Abr. de 2017
Method one: indexing:
M(1:1+size(M,1):end) = 0
Method two: eye:
M.*~eye(size(M))
1 comentario
Stephen23
el 19 de Abr. de 2017
A strict interpretation of the question requires only diagonals equal to one get changed to zero: this is easy to implement with eye:
M.*~(eye(size(M)) & M==1)
Roger Stafford
el 19 de Abr. de 2017
If your matrix M is not square and if you only want those diagonal elements changed to zero “if it is 1”, then you can do the following. Other diagonal elements not equal to one will remain unchanged. (Your description was perhaps a little ambiguous on this latter point.)
[m,n] = size(M);
d = 1:m+1:min(m^2,m*(n-1)+m);
f = find(M(d))==1;
M(d(f)) = 0;
4 comentarios
Zeina Abdullah
el 5 de En. de 2022
@Stephen can you help me by try to answer the last question in my profile please
Christine Tobler
el 23 de Mayo de 2017
Editada: Christine Tobler
el 23 de Mayo de 2017
If you are using the graph/digraph classes, you can also tell the constructor not to insert any self-loops for the diagonal elements:
g = graph(A, 'omitSelfLoops');
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