Divide and expand matrix
2 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Andrew Poissant
el 7 de Jul. de 2017
I have a 600x600 matrix with integer values in each cell. What I want to do is expand that matrix into a 6,000x6,000 matrix. However, since it is being expanded to 10x its size, I need to scale the integer in each cell accordingly. So if I have the value 10 in row 1 column 1 of the 600x600 matrix, I now need the value 1 in rows 1-10 columns1-10. Does anyone have any ideas how to do this?
2 comentarios
Geoff Hayes
el 7 de Jul. de 2017
Andrew - what happens if the value in row 1 column 1 (or any other position) is not divisible by ten? (Since you are saying that the value 10 at (1,1) must be 1 in (1:10,1:10).)
Respuesta aceptada
dpb
el 7 de Jul. de 2017
Editada: dpb
el 8 de Jul. de 2017
Something like this you mean:
>> x=reshape(1:9,3,3) % starting sample input array
x =
1 4 7
2 5 8
3 6 9
>> N=2; % choose a multiplier size factor
>> xnew=cell2mat(arrayfun(@(x) repmat(x,N,N),x,'uniform',0))
xnew =
1 1 4 4 7 7
1 1 4 4 7 7
2 2 5 5 8 8
2 2 5 5 8 8
3 3 6 6 9 9
3 3 6 6 9 9
>>
ADDENDUM To divide down is as you surmise, just use N as divisor in the anonymous function--for the same x
>> cell2mat(arrayfun(@(x) repmat(x,N,N)/N,x,'uniform',0))
ans =
0.5000 0.5000 2.0000 2.0000 3.5000 3.5000
0.5000 0.5000 2.0000 2.0000 3.5000 3.5000
1.0000 1.0000 2.5000 2.5000 4.0000 4.0000
1.0000 1.0000 2.5000 2.5000 4.0000 4.0000
1.5000 1.5000 3.0000 3.0000 4.5000 4.5000
1.5000 1.5000 3.0000 3.0000 4.5000 4.5000
>>
ADDENDUM 2: Of course, if N is constant as above, it can come outside the anonymous function--
cell2mat(arrayfun(@(x) repmat(x,N,N),x,'uniform',0))/N
If it were a positional transform, the anonymous function could have a second argument of size(x) if need be or the dot division operator or automagic singleton expansion in later versions could come into play depending on just what a particular transformation looked like.
2 comentarios
Más respuestas (1)
Geoff Hayes
el 7 de Jul. de 2017
Andrew - what have you tried so far? Suppose mtx1 is your 600x600 matrix and mtx2 is your 6000x6000 matrix. The mapping of your elements from mtx1 to mtx2 is as follows
mtx1(1,1) --> mtx2(1:10,1:10)
mtx1(1,2) --> mtx2(1:10, 11:20)
mtx1(1,3) --> mtx2(1:10,21:30)
...
mtx1(2,1) --> mtx2(11:20,1:10)
...
mtx1(3,1) -->mtx2(21:30,1:10)
So one way to do this, is to iterate over each row and column of mtx1 and then map it to the correct "block" of mtx2 probably something like
mtx2((r-1)*10+1:r*10,(c-1)*10+1:c*10) = mtx1(u,v)/10;
where r and c are the indices to the current row and column respectively.
0 comentarios
Ver también
Categorías
Más información sobre Logical en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!